The New Sudoku Players' Forum

[udosuk]

(c) Build a tetrahedron.

What about this?

[Cec]

Gee! I thought these riddles would be easy to reply to

zonkjonk's first two answers are probably right.

I agree.
Cec

"Build a tetrahedron."
Alternative answer to (a):
Sagarmatha (Sanskrit)
Chomolungma/Qomolangma (Tibetian)
Zhumulangma Feng/Shengmu Feng (Chinese)"...

If I'm correct in assuming these are three mountains and also assuming they are not as high as Mount Everest then Mount Everest would be the correct answer because it still existed even though it hadn't been discovered.
Cec

"build a tetrahedron")

I hadn't forgotten you udosuk and this is correct. A "tetrahedron" is defined as a triangular pyramid bounded by four plane triangles which can be formed by the six matches - three of the matches form the base of the triangle and the other three matches being joined at a common apex of a triangle formed by joining the other end of each of these three matches to each corner of the base triangle.

"Surely these names are earlier than "Mount Everest""...

Unless I'm missing something here, I can't see how being "earlier" is relevant to the question?
Cec

"..What's in a name? that which we call a mountain
By any other name would be as high."

Hey! this is another riddle and I'm no good at answering these I'm still curious though what it means?

".. lay four matches to form a square then 2 diagonally across?
I wish I knew how to draw a picture here "

I'm still not ruling your answer out zonkjonk notwithstanding udosuk's above correct solution - lets see if we can communicate like this:

Code: Select all

 A          B



  C          D 

Assuming ABCD form the four corners of the square and EF and GH are the other two matches. Can you verbally describe how you would place matches EF and GH to form the four equal triangles?

Cec

[MCC]

Alternative answer to (a):
Sagarmatha (Sanskrit)
Chomolungma/Qomolangma (Tibetian)
Zhumulangma Feng/Shengmu Feng (Chinese)"...

If I'm correct in assuming these are three mountains and also assuming they are not as high as Mount Everest then Mount Everest would be the correct answer because it still existed even though it hadn't been discovered.
Cec

White man came found high mountain name him Mount Everest, locals already name him.

So, does the fact that Mount Everest had a name before it became Mount Everest ruin the riddle

"..What's in a name? that which we call a mountain
By any other name would be as high."

Hey! this is another riddle and I'm no good at answering these I'm still curious though what it means?

Not a riddle, just a play on Shakespeare.


MCC

[udosuk]

Alternative answer to (a):
Sagarmatha (Sanskrit)
Chomolungma/Qomolangma (Tibetian)
Zhumulangma Feng/Shengmu Feng (Chinese)"...

If I'm correct in assuming these are three mountains and also assuming they are not as high as Mount Everest then Mount Everest would be the correct answer because it still existed even though it hadn't been discovered.
Cec

White man came found high mountain name him Mount Everest, locals already name him.

So, does the fact that Mount Everest had a name before it became Mount Everest ruin the riddle

Exactly the point. The 3 lines of names were alternative names to the same mountain... See this article... I did state they're alternative answers and is not ruling out "Mount Everest" as being correct itself...

But "discovery of Mount Everest" is a subjective event. To the Western world it occured during the 19th century but surely way before that time it was already discovered by the Nepalese, Tibetans and Chinese...

[Cec]

Alternative answer to (a):
Sagarmatha (Sanskrit)
Chomolungma/Qomolangma (Tibetian)
Zhumulangma Feng/Shengmu Feng (Chinese)..... I did state they're alternative answers and is not ruling out "Mount Everest" as being correct itself...)"...

I must confess udosuk of being unaware of this history as obviously was also the case of the author of the book where I read this riddle. As such I now see your answer as also being correct giving you another elephant stamp.

So, does the fact that Mount Everest had a name before it became Mount Everest ruin the riddle

Because of this fact I'd have to say it does. I move we keep this fact a secret to keep this riddle "alive". I'm not waiving my hands in the air saying " Teacher, I know, I know" - I'm waiving a white flag yelling '"I surrender, I surrender"

Cec

[Cec]

"..Build a tetrahedron...".

udosuk's tetrahedron would look like this:


Cec

[udosuk]

So, in the mood of matchsticks puzzles, here is another one:



Move 2 matches and nothing else so that there are no triangles left...

[Chessmaster]

What number comes next

[0,1,] 2,5,26,677,458330,210066388901,44127887745906175987802

Code: Select all

F(x) = (F(x-1) * F(x-1)) + 1

Ruud.

Correct

[Cec]

"Move 2 matches and nothing else so that there are no triangles left...

I'm still thinking.
Cec

[MCC]

Is this function correct?

Code: Select all

F(x) = (F(x-1) * F(x-1)) + 1

Shouldn't it be :

Code: Select all

F(x) = F((x^2) + 1)

MCC

[Cec]

"..Shouldn't it be :

Code: Select all

F(x) = F((x^2) + 1)

MCC

This is taking me back many, many years, but if (x^2) means x squared then I agree with MCC.
Cec

".. Move 2 matches and nothing else so that there are no triangles left..."

I've given up thinking.. This is a real "teaser" ....dying to know the answer?
Cec

[Ruud]

2 matches moved.

1 diamond,
1 5-sided shape,
2 AT's (almost triangles)

no triangles.

Ruud.

[Cec]

".. no triangles..."

No triangles? I can still see one under the two matches that were moved.

Cec

[udosuk]

No triangles? I can still see one under the two matches that were moved.

You're right Cec, Ruud's answer is not the one...

Hint: Lateral thinking is required...

Shouldn't it be :

Code: Select all

F(x) = F((x^2) + 1)

Would that makes F(0)=F(1)=F(2)=F(5)=F(26)=...?

Are you sure you weren't meaning:

Code: Select all

F(x+1)=(F(x))^2+1

[MCC]

It's been many moons since I had anything to do with functions and how they're written.

I know this function should show an iterative process, how about:

Code: Select all

F(x) = (x^2) + 1

MCC