Here is a 6x6 puzzle:
https://andrewspuzzles.blogspot.com/202 ... -by-6.html
International_DBA wrote:Here is a 6x6 puzzle:
https://andrewspuzzles.blogspot.com/202 ... -by-6.html
International_DBA wrote:Bonjour Denis,
Est-ce qu'on est permis de parler francais ici?
Je viens de creer un autre hidoku.
Andrew
https://andrewspuzzles.blogspot.com/202 ... -by-5.html
,--------------------,
| __ __ __ 19 __ | 5
| __ 25 __ __ __ | 4
| __ 15 __ __ __ | 3
| __ __ 01 __ 03 | 2
| __ __ __ __ __ | 1
'--------------------'
a b c d e International_DBA
. (16)a2 or (16)a3 imply that we cannot reach 19.
. (16)a4 forces (17)b5 so no number for a5.
. (16)b2 forces (17)c3 and,
. if (18)c4, then the route from 14 to 3
has to pass through a2,a1,b1,c1,d1,e1,d2,
not reaching 04. Notice that a5,b5,c5 is
taken for numbers 24,23,22.
. if (18)d4, then (20)e5, (21)e4 and the
path to 25 has to pass through c4,d3 so
we must have (2)d1,(4)e1,(5)d2, (6)c1,
(7)b1, etc and the connection to 15 is lost.
. (17)b5 forces (18)c5, (24)a5, (23)a3, etc,
and the connection between 25 and 19 is lost.
. (17)c5 forces (18)d4, (20)e5, (21)e4,
(24)b5, (23)a5; connection to 21 is lost.
. (17)c3 forces (18)d4, (20)e5,(21)a4;
and the connection between 21 and 25 is lost.
. (17)d3 forces (18)d4 or (18)e4:
. in the first case we need (20)e5
and (24)c5 and the connection between
20 and 25 is lost;
. in the second case, i.e., (18)e4,
forces (20)e5, (21)d3, reaching a
problem in cells e1, e3 (only one access)
,--------------------,
|*22 *21 *20 19 *18 | 5
|*23 25 *16 *17 __ | 4
|*24 15 __ __ __ | 3
| __ __ 01 __ 03 | 2
| __ __ __ __ __ | 1
'--------------------'
a b c d e
. (2)d3 creates a problem at e3,e4,
that can be accesses in only one way
. (2)d2 makes e4 to be reached in only
one way.
,--------------------,
|*22 *21 *20 19 *18 |
|*23 25 *16 *17 *07 |
|*24 15 *09 *08 *06 |
|*14 *10 01 *05 03 |
|*13 *12 *11 *02 *04 |
'--------------------'
(solve Hidato geometric 5 25
. . . 19 .
. 25 . . .
. 15 . . .
. . 1 . 3
. . . . .
)