For U26, my solver suggest about 12 AICs.
I picked up the three best to start
.26...9....5.6.4.....9.7...9..1....5.4....28.5....3..4...6.2.....9.5.7....1...85.
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134x7k8 2 6 |34z5a8 1348 145A8 |9 137 1378
137K8 9 5 |2m38 6 1É8é |4 1237 12378
1348 1e38 34l8 |9 12M34x8 7 |5 1236b 1236B8
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9 3678 2c378 |1 2C4d78 4D6f8 |3G6g 3Ê7ê 5
1e36f 4 3ë7Ë |5A7a 7Ì9ì 5a6F9n |2 8 1E3s7Â9h
5 1E6g78 2C78 |2M78 2789h 3 |1g6G 179H 4
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348 5 34L7i8 |6 1p347I8ä9È 2 |1G3g 134o9h 139
2J3468 368 9 |348 5 1P48 |7 12R34O6B 1236
2j34y6 367I 1 |347á 3479 4n9N |8 5 2J36À9È
[]2r4c5-C/2r6c4_2r2c4/2r2c8_2r38c8/4r8c8|*r38c8_4r7c8/4r7c13_4r89c1/6r89c1|*r89c1_6r4c6/2r4c5-C|*r4c56
r4c3=2[]9r5c6-n/9r5c5_7r5c5/7r7c5_7r7c3/8r37c3|*r37c3_8r46c3/8r4c2_8r4c356/6r4c6|*r4c356_6r5c6/9r5c6-n
r9c6=9[]1r7c5-p/4r7c135|*r7c135_4r7c8/4r7c13_4r89c1/1r5c1|*r589c1_1r5c9/1r6c7_1r7c7/1r7c5-p
r8c6=1EDIT 1
Although it would have been possible to continue with the first grid, one could expect simplest chains applying the three fixs.
The four AICs below are enough to crack the grid.
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134x7k8b 2 6 |3Ç4z5a 1n34 4a5A |9 137 1378B
1p37K 9 5 |2G3g 6 8 |4 1237 1237
1348 1e38 34l8 |9 1N2g34x 7 |5 1236c 1236C8b
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9 3s6È78d 2 |1 4a78D 4A6a |3H6h 3Å7å 5
1e36a 4 3Æ7æ |5A7a 7F9f 5a6A |2 8 1E3s7Â9F
5 1E6h78 7Ä8ä |2g78m 2G789F 3 |1h6H 179f 4
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348 5 34L7i8 |6 347I8m 2 |1H3h 1Î34o9F 139f
2J3468 368 9 |348M 5 1 |7 2R34O6C 236
2j34y6 367I 1 |347á 347 9 |8 5 2J36À
[]8r6c4-m/8r6c3_7r6c3/7r7c3_7r7c5/8r7c5-m
[]7r6c4/2r6c4_2r2c4/2r2c8_2r38c8/4r8c8|*r38c8_4r7c8/4r7c13_4r89c1/6r89c1|*r89c1_7r5c4/7r6c4
[]3r7c5/3r7c789_4r7c8/4r7c13_4r89c1/6r89c1|*r89c1_4r4c5/8r4c5_8r4c2/8r6c3_7r6c3/7r7c3_7r7c5/3r7c5
[]6r9c2/7r9c2_7r7c3/7r6c3_8r6c3/8r4c2_8r4c5/4r4c5_6r89c1/6r9c2
Here is the chain found by the solver for 8r6c4 on the first grid.
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[]8r6c4/8r8c4_8r7c5r8c6/7r7c5|*r7c5r8c6_7r7c3/8r37c3|*r37c3_8r46c3/8r4c2_8r4c356/6r4c6|*r4c356_6r89c1/4r89c1|*r89c1_4r7c13/4r7c8_4r8c8/2r38c8|*r38c8_2r2c8/2r2c4_2r6c4/8r6c4