Sorry that was rude. Pardon my French.

Now I’ve got a naked hextle (or is it sextle?). Where is this going to end?

50 posts
• Page **2** of **4** • 1, **2**, 3, 4

So many questions, so few answers. Are you still interested in how I’m going with this puzzle? Yes? Good. Sadly, I’m still in solution-mode. I whipped home at lunchtime to print off another copy of the grid but oddlly they’d closed down the site and I had to use my old scribbled-over one – that was a little bit tricky when I was pretending to be working diligently at the same time, but I managed. However. I got almost to the end then found I had a multiple solution! It’s not one of those is it? I can’t face going back to it, so now I’m going to try the other kind of solution I know of and hope that helps.

See, Paul, I can do a sad face too. Could you please wipe yours off, I get a guilt trip every time I open up!

See, Paul, I can do a sad face too. Could you please wipe yours off, I get a guilt trip every time I open up!

- emm
**Posts:**987**Joined:**02 July 2005

I'm probably the only person still visiting this thread – oh well, it can be my personal record.

Dear Diary, Day 3: Slaying the Samunampure.

I feel like I've been to the Slough of Despond and back over this puzzle, but then last night while I was sleeping, the light came on – funny how it does that, as if it’s waiting to catch all that regular clutter off guard. Anyway, it came to me in a blinding flash - I’d been so obsessed by the dotted lines, I’d forgotten all about the normal ‘1-9 in every rbc’ rule of Sudoku!! Such a simple thing in the end. Talk about myopic! Well, I won’t make that mistake again. Now … I need to find that second grid, but I don’t think Paul’s talking to me anymore

Dear Diary, Day 3: Slaying the Samunampure.

I feel like I've been to the Slough of Despond and back over this puzzle, but then last night while I was sleeping, the light came on – funny how it does that, as if it’s waiting to catch all that regular clutter off guard. Anyway, it came to me in a blinding flash - I’d been so obsessed by the dotted lines, I’d forgotten all about the normal ‘1-9 in every rbc’ rule of Sudoku!! Such a simple thing in the end. Talk about myopic! Well, I won’t make that mistake again. Now … I need to find that second grid, but I don’t think Paul’s talking to me anymore

- emm
**Posts:**987**Joined:**02 July 2005

Glad you solved it Em!

Now, Paul, please can you offer some tips/hints to get me going on that second puzzle. I haven't had a lot of time to look at it over the weekend but I'm completely stumped. I've got the 7-cage 28 is less than 4-cage 29 is less than 4-cage 30 and some other candidates in the right hand column but that's about it - no actual entries at all. Help

Now, Paul, please can you offer some tips/hints to get me going on that second puzzle. I haven't had a lot of time to look at it over the weekend but I'm completely stumped. I've got the 7-cage 28 is less than 4-cage 29 is less than 4-cage 30 and some other candidates in the right hand column but that's about it - no actual entries at all. Help

- CathyW
**Posts:**316**Joined:**20 June 2005

Well, it was a while ago I did it now (and I had help), but here's a go:

Look at the 7s. There's got to be a 7 in the 28-cage you've found, as well as in the 29-cage (which has to be 9875) and the 30-cage (must be 9876). The 28-cage and the 30-cage together make up one whole box, with one cell in each cage that spills out into a different box. So at least one of their 7s must go in a spillover box. If the 28-cage had the 7 in its spillover box, there'd only be one place the 7 could go in the huge 9-cell cage that's mostly in box 5. Those two 7s would leave nowhere for the 7 in the 29-cage to go. (I guess this is T&E really, but I'm much less fussy about it in these puzzles). So it has to be the 30-cage that has its 7 in the spillover box.

I don't know how much that'll help, but it's a start.

Look at the 7s. There's got to be a 7 in the 28-cage you've found, as well as in the 29-cage (which has to be 9875) and the 30-cage (must be 9876). The 28-cage and the 30-cage together make up one whole box, with one cell in each cage that spills out into a different box. So at least one of their 7s must go in a spillover box. If the 28-cage had the 7 in its spillover box, there'd only be one place the 7 could go in the huge 9-cell cage that's mostly in box 5. Those two 7s would leave nowhere for the 7 in the 29-cage to go. (I guess this is T&E really, but I'm much less fussy about it in these puzzles). So it has to be the 30-cage that has its 7 in the spillover box.

I don't know how much that'll help, but it's a start.

- PaulIQ164
**Posts:**533**Joined:**16 July 2005

Far be it for me to derail this thread into off-topic but I'd really like to know, are these puzzles different to the Kakuro that's currently being offered as a Sudoku alternative? Kakuro Or are they just a different way of presenting the same thing?

Luna

Luna

- lunababy_moonchild
**Posts:**659**Joined:**23 March 2005

OK - it helped a bit. I've progressed this far:

Also, obviously, have 6s as possible candidates in r1,c5; r2c5; r3c5; r4c1; r4c2 and r4c3.

The 3-cage in the top right box can sum to a maximum of 11 (2+3+6), which would make the 4-cage sum to 29 leaving 1 and 4 as a pair for the other cells, but it could also be 10 (2+3+5) and it would still be greater than the straight 3-cage to its left which could sum to 7 or 8 or 9 (or 10 if the top right 3-cage sums to 11) (can't be 6 as then I'd have no candidates left in r1c9!).

Could you confirm that what I've got so far is correct and I'll muse it on it a bit more.

- Code: Select all
`. . . . . . . . [123]`

. . . . . . [569] . [123]

. . . . . . [569] 8 7

. . . . . . [123457] [12345] [123]

. . . . . . [123457] [12345] 6

. . . . . 6 [123457] 9 8

2 [13] [13] 6 [59] [59] 8 7 4

6 5 8 [24] [24] 7 [13] [13] 9

9 [47] [47] [138] [138] [138] [26] [26] 5

Also, obviously, have 6s as possible candidates in r1,c5; r2c5; r3c5; r4c1; r4c2 and r4c3.

The 3-cage in the top right box can sum to a maximum of 11 (2+3+6), which would make the 4-cage sum to 29 leaving 1 and 4 as a pair for the other cells, but it could also be 10 (2+3+5) and it would still be greater than the straight 3-cage to its left which could sum to 7 or 8 or 9 (or 10 if the top right 3-cage sums to 11) (can't be 6 as then I'd have no candidates left in r1c9!).

Could you confirm that what I've got so far is correct and I'll muse it on it a bit more.

- CathyW
**Posts:**316**Joined:**20 June 2005

50 posts
• Page **2** of **4** • 1, **2**, 3, 4