I have found one mathematical way to solve the Sudoku , it is systematic and step-by and guarantee( I feel so ) to solve any valid Sudoku, please help to review it.
http://www.scribd.com/doc/39235249/How-to-Solve-Sudoku-Mathematically
Also I need you expert comment on number of possible valid Sudoku, using this method I arrived at different figure that what it is now most agreed number, Please comment.
*-----------*
|183|7..|.9.|
|2.4|..6|3..|
|.75|9..|...|
|---+---+---|
|...|.61|85.|
|.3.|...|.1.|
|.41|57.|...|
|---+---+---|
|...|..7|12.|
|..2|8..|5.9|
|.1.|..5|478|
*-----------*
00530000080000002007001050040000530001007000600320008009004000030000009700
In B3N3 Y=9 is unique
*-----------*
|..5|3..|...|
|8..|...|.2.|
|.7.|.1.|5..|
|---+---+---|
|4..|..5|3..|
|.1.|.7.|..6|
|..3|2..|.8.|
|---+---+---|
|.6.|5..|..9|
|..4|...|.3.|
|...|..9|7..|
*-----------*
Need some feedback from programmers also, whether the logic is simplified?
Part-2
@ surbier Â» Sun Oct 31, 2010 2:28 am
Regarding â€œIn B3N3 Y=9 is unique â€œ
Page no. 16 In B3N3 Y=9 is unique , Means since Y in the cell B3N9 is 9 so in Column Y=9 is not possible i.e. Y=9 is unique coordinate for that cell , it means we can eliminate Y=9 from that column. - Thanks
So on B8N3 Y=5 is not possible and Y=6 becomes unique
agreed. there is no other subset in this puzzle at this particular state.But from B5N1 x={46}, y={46}, which can be either 44 or 66, I cannot conclude that B5N6 is also either 44 or 66.