There must be a 9 in column 1.
It cannot be in the bottom-left block because the only options for the left-hand 13-cage in that block are 1,5,7 or 2,4,7 or 2,5,6. (The only set of three numbers that sums to 13 and includes a 9 is 1,3,9 which is blocked as an option since there is already a 3 in column 1.)
It cannot be in the centre-left block because the 9 in this block is in row 2, and column 1 in this row is already occupied by an 8.
The 9 in column 1 must therefore be in the top-left block.
Therefore the 9 in the top-left block must be in column 1.
It cannot be in row 1 or 3 due to 9s already in these rows.
Cell r2c1 is therefore a 9.
Good luck!