## who am i

Anything goes, but keep it seemly...
Cec wrote:.... Nice one Bill ....

Not original, though.

Actually, nobody would pick nine, because they would immediately realize they were falling into a trap of some kind.

My point was that "what's the next number" puzzles are never very good. It's always possible to run a polynomial through any N points on an xy-plane, and thus to come up with any answer you want.

Bill Smythe
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I picked 9 because I thought it was a joke like my sequence.

In fact, if you'd read the thread, nobody would not pick nine
mikejapan

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### who am I?

mikejapan wrote:"I picked 9 because I thought it was a joke like my sequence...."

Yes, and that's why I picked 9 for the same reason.

Cec
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Smythe Dakota wrote:It's always possible to run a polynomial through any N points on an xy-plane, and thus to come up with any answer you want.

So could you run one of those polly-normal jobbies and come up with the answer"9"?
mikejapan

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mikejapan wrote:#8=hhh

#9=hhh

I don't quite understand...

mikejapan wrote:So could you run one of those polly-normal jobbies and come up with the answer"9"?

Code: Select all
`y=2x-1+(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)...(x-anything)`
is one example.
Another example is y=2x-1.
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999_Springs

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y=2x-1

So if y = 9 then x = 5
or if x = 9 then y = 17

So what?
mikejapan

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999_Springs wrote:Another example is y=2x-1.

What an odd way to look at this problem, no wonder all of you got fooled by Bill! One glance at the sequence should reveal the obvious answer:

y = 8½-|2(x-4¾)|

Challenge: Create a polynomial that continues Bill's sequence to X=6 (Y=9).

RW
RW
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see here

JPF
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