this puzzle is weird to me..

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Postby daj95376 » Wed Apr 08, 2009 7:35 pm

ronk wrote:
daj95376 wrote:(8)r6c2=(8)r5c2-(8=2)r5c7-(2=9)r8c7-(9)r9c9=(9-8)r9c5=(8)r6c5-(8)r6c2 => [r5c6],[r6c46]<>8

Note: The third entry is a continuous AIC loop.

ronk: Sorry, but my thoughts have switched from NL notation to Eureka/AIC/??? notation anymore.

Why anyone would want to clutter the notation -- parentheses, often writing the same candidate twice, and writing the same cell twice for AHSs -- is beyond me. BTW in AIC notation it's 'loop' not 'continuous loop', and it's frequently written as ...

(8)r6c2=(8)r5c2-(8=2)r5c7-(2=9)r8c7-(9)r9c9=(9-8)r9c5=(8)r6c5-loop => [r5c6],[r6c46]<>8

I see you're hanging on to those square brackets for the eliminations though.:) Cool:!:

Thanks for the update on using loop at the end. I like it!

I originally stayed with NL notation because the Eureka notation was often longer and the original examples I saw were complex with imbedded structures like AUR and ahp and AARFTCP. (AARFTCP -> almost almost realistic for the common person)

However, NL notation left me cold when it came to identifying some inferences as either strong or weak. I'm much more comfortable reading/writing chains now because the inferences stand out for common chains in Eureka notation.

Yes, I'm holding onto the square brackets for the eliminations. I feel that it helps delineate the chain from the eliminations. Just a quirk of mine.

In order to reduce the notation when an X-Chain occurs inside a Eureka chain, I shorten the notation to (n){...} when practical.

Finally, I was expecting a comment from someone on the fact that the last two cells in my first chain could have been written ... (2)r8c7-(2=9)r9c9. Is there a preferred choice here?
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Postby ronk » Wed Apr 08, 2009 8:52 pm

daj95376 wrote:Finally, I was expecting a comment from someone on the fact that the last two cells in my first chain could have been written ... (2)r8c7-(2=9)r9c9. Is there a preferred choice here?

I'm not an AIC notation afficionado, but I think it's the later.
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Postby DonM » Wed Apr 08, 2009 9:04 pm

daj95376 wrote:Finally, I was expecting a comment from someone on the fact that the last two cells in my first chain could have been written ... (2)r8c7-(2=9)r9c9. Is there a preferred choice here?


IMO, not really all that important, though some may prefer it -the above is how I usually do it though if the chain allows it, I usually start the chain with the bivalue cell strong link. There's a lot of flexibility in the Eureka/AIC notation and people vary in the way they express these sorts of things. fwiw: A lot of people may not be aware that Myth Jellies own notation predated the Eureka notation. It was after Ruud, with the help of several people, including Myth (as I recall) fine-tuned the Eureka notation, that Myth 'converted' also.

Here's an example:
Eureka notation: (3)r2c7=(3-7)r6c7=(7)r6c3...
Myth's original: 3[r2c7]=3[r6c7]-7[r6c7]=7[r6c3]... (this example is from the period when I started converting myself so I was never totally familiar with all aspects of Myth's notation. He probably did the above as 3[r2c7]=(3-7)[r6c7]=7[46c3]...

And another: 3[r2c7]=3[r6c7]-(3=2727)[r46c3]-2[r456c1]... ie. an als->group.
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Postby aran » Wed Apr 08, 2009 11:26 pm

ronk wrote:Why anyone would want to clutter (...) often writing the same candidate twice (...)

ronk wrote:I'm not an AIC notation afficionado

Clutter detected.
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Postby ronk » Thu Apr 09, 2009 12:41 am

*** off-topic ***

aran wrote:
ronk wrote:Why anyone would want to clutter (...) often writing the same candidate twice (...)
...
I'm not an AIC notation afficionado
Clutter detected.

Well, there are fine points ... and then there are very fine points. Surely you know it takes an afficionado for the latter.
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Postby ttt » Thu Apr 09, 2009 8:01 am

::Off Topic::
DonM wrote:Here's an example:
Eureka notation: (3)r2c7=(3-7)r6c7=(7)r6c3...
Myth's original: 3[r2c7]=3[r6c7]-7[r6c7]=7[r6c3]... (this example is from the period when I started converting myself so I was never totally familiar with all aspects of Myth's notation. He probably did the above as 3[r2c7]=(3-7)[r6c7]=7[46c3]...
And another: 3[r2c7]=3[r6c7]-(3=2727)[r46c3]-2[r456c1]... ie. an als->group.

Why don't: [3]r2c7=[3-7]r6c7=[7]r6c3... no need to use "Shift key":D

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Postby hobiwan » Thu Apr 09, 2009 4:52 pm

::Off Topic::
ttt wrote:Why don't: [3]r2c7=[3-7]r6c7=[7]r6c3... no need to use "Shift key":D

You apparently never used a german keyboard:)
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Sorry..............

Postby sarker306 » Fri Apr 10, 2009 4:03 pm

I m very sorry to interfere in such a wonderful comments, but I am trying to find out a very short chain here.
Please help.
Code: Select all
.---------------------.---------------------.---------------------.
| 1      3569   35    | 4      2      69    | 56     8      7     |
| 679    679    57    | 156    689    18    | 2      3      4     |
| 2      4      8     | 56     7      3     | 1      9      56    |
:---------------------+---------------------+---------------------:
| 3679   1      357   | 8      346    47    | 5679   56     2     |
| 8      67     2     | 9      1      5     | 67     4      3     |
| 3679   35679  4     | 236    36     27    | 5679   1      8     |
:---------------------+---------------------+---------------------:
| 4      8      1     | 7      569    69    | 3      2      59    |
| 5      2      6     | 13     389    18    | 4      7      19    |
| 37     37     9     | 12     45     24    | 8      56     156   |
'---------------------'---------------------'---------------------'
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