I also applied (manually or by software, it's just a difference in time) to the best ranked of the superior puzzles, the #74 by Vidarino.
Hard indeed. After a first pass I stuck at:
- Code: Select all
3458 35789 3489 | 1 458 6 | 5789 2789 2789
4568 5678 1 | 245 9 2458 | 3 278 2678
568 2 689 | 7 58 3 | 5689 4 1
-----------------------------------------------------
7 368 2 | 69 1368 89 | 4 189 5
1 4 38 | 259 3578 2589 | 789 6 789
9 68 5 | 46 14678 48 | 2 178 3
-----------------------------------------------------
2346 1 3469 | 8 46 7 | 69 5 2469
4568 5689 7 | 4569 2 459 | 1 3 4689
24568 5689 4689 | 3 456 1 | 6789 2789 246789
Far from being solved, and with a lot of couples to test.
But I noticed that in the central block the 4 couples are connected, i.e. they admit only 2 solutions.
So I found that r4c4=6 is correct, r4c4=9 is not
With r4c4=6 the resulting scheme was:
- Code: Select all
3458 35789 3489 | 1 458 6 | 5789 2789 2789
4568 578 1 | 25 9 245 | 3 278 2678
568 2 689 | 7 58 3 | 5689 4 1
----------------------------------------------------
7 38 2 | 6 13 9 | 4 18 5
1 4 38 | 25 357 25 | 789 6 789
9 6 5 | 4 17 8 | 2 17 3
----------------------------------------------------
2346 1 3469 | 8 46 7 | 69 5 2469
4568 58 7 | 9 2 45 | 1 3 468
24568 589 4689 | 3 456 1 | 6789 2789 246789
(forget the first 2 vertical lines, introduced by the code)
Again, I had to choose, and my software confirmed that for r5c2 the right solution was a 3. Result:
- Code: Select all
3458 5789 349 | 1 458 6 | 5789 279 2789
4568 578 1 | 25 9 245 | 3 27 2678
568 2 69 | 7 58 3 | 5689 4 1
---------------------------------------------------
7 3 2 | 6 1 9 | 4 8 5
1 4 8 | 25 3 25 | 79 6 79
9 6 5 | 4 7 8 | 2 1 3
---------------------------------------------------
2346 1 3469 | 8 46 7 | 69 5 2469
4568 58 7 | 9 2 45 | 1 3 468
24568 589 469 | 3 456 1 | 6789 279 246789
Finally, I noticed that in the upper center block 2 is present only in the second row, so it can be eliminated from the same row of the two side blocks. In particular r2c8=7, what allows to proceed up to solution.
- Code: Select all
3 7 4 | 1 8 6 | 5 9 2
6 5 1 | 2 9 4 | 3 7 8
8 2 9 | 7 5 3 | 6 4 1
----------------------
7 3 2 | 6 1 9 | 4 8 5
1 4 8 | 5 3 2 | 7 6 9
9 6 5 | 4 7 8 | 2 1 3
----------------------
2 1 3 | 8 6 7 | 9 5 4
4 8 7 | 9 2 5 | 1 3 6
5 9 6 | 3 4 1 | 8 2 7
By the way, when I operate manually I always follow that purging strategy, and the same for triplets of numbers forming three groups in a block or along a row or a column (those numbers can be eliminated from the other positions of the block, row or column). Sorry for my bad way of exposition.
My way of preceeding is rather rough and it must be supported by a simple software to test between alternate double solutions in an acceptable time. But I showed that even hard schemes can be solved in a short time.