Two [edit: non-intersecting] groups identically colored (amber) in the same unit (box 3) are a contradiction and, therefore, the candidates (the 2s) thusly colored may be eliminated from *all* cells bearing that color. Alternatively, placement of a candidate (2s) may be made in all groups of *single* cells that bear the complementary color (pink).
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Grouped implication chains are:
r12c9=2 => r6c9<>2 => r6c5=2 => r3c5<>2 => r3c78=2 (grouped turbot fish)
amber <--> pink <---> amber <--> pink <---> amber
OR
r12c9=2 => r6c9<>2 => r6c5=2 => r4c4<>2 => r12c4=2 => r3c5<>2 => r3c78=2 (grouped 7-sided x-cycle)
amber <--> pink <---> amber <--> pink <---> amber <--> pink <---> amber
Read r12c9=2 to mean "r1c9=2 OR r2c9=2"
and a (fictitious) r12c9<>2 to mean "r1c9<>2 AND r2c9<>2"
The puzzle in SS form:
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*-----------*
|...|.1.|...|
|...|.7.|...|
|61.|8.9|..3|
|---+---+---|
|4..|.3.|.19|
|1..|96.|..7|
|769|5.1|38.|
|---+---+---|
|..6|.9.|..5|
|..2|.5.|19.|
|951|482|736|
*-----------*