[Edit] The explanation given here is not water-tight, and the eliminations are therefore not proven. See <here>. In this puzzle there is an Almost Multi-sector Locked Set nested inside an Almost Shark.
....5...9.5.1...3.....37...2..6..8...6..1..7...4..5.....9.....2.3...1.6.8.....4..;136;elev;117;2BN D1D3
- Code: Select all
v v v v H A
*-------------------------*-------------------------*-------------------------* Min Max
>| 1367-4 12478 1367-28 | 248 5 2468 | 167-2 1248 9 |< 1
| 4679 5 2678 | 1 2489-6 2489-6 | 267 3 4678 | 2
| 1469 2489-1 1268 | 2489 3 7 | 1256 248-15 14568 | 3
*-------------------------*-------------------------*-------------------------*
>| 2 179 1357 | 6 479 349 | 8 1459 135-4 |< 2
| 359 6 358 | 2489-3 1 2489-3 | 2359 7 345 | 2
>| 137-9 1789 4 | 23789 2789 5 | 136-29 129 136 |< 1
*-------------------------*-------------------------*-------------------------*
>| 1567-4 147 9 | 34578 4678 3468 | 1357 158 2 |< 2
| 457 3 257 | 2489-57 2489-7 1 | 579 6 578 | 2
>| 8 127 1567-2 | 23579 2679 2369 | 4 159 1357 |< 2
*-------------------------*-------------------------*-------------------------* - -
^ ^ ^ ^ 8 9
(2489)AlmostShark:r14679c1379 Home Min Truths = 8, Away Max Truths = 9
Home
PEs r1c138, r3c9, r6c17, r7c1, r9c3 <> 2489
Away
PEs r2c56, r3c8, r5c46, r8c45 <> 13567
This puzzle has an Almost Shark where the minimum number of truths in the Home cells is one less than the maximum number of truths in the Away cells. The
Potential Eliminations are shown for both cell sets but we know that just one of these is invalid.
Noticing that boxes 4679 nearly contain an SK Loop, the equivalent Almost Multi-sector Locked Set can be composed:
(35)r5,(89)b4,(17)c2,(24)b7,(57)r8,(89)b9,(15)c8,(249)b6 [16 available intersection cells occupied by 17 candidates]
To reduce this to a locked set one of the digits must be eliminated, and because this pattern is contained in 4 boxes, it must therefore occur in an uncovered cell in one of them.
The Shark PEs cover all the possibilities for locating the evicted digit, so one of these cells must hold the invalid PE which allows the eliminations in the other 5 boxes to be made (14 eliminations in 11 cells).
There must be many ways to view this situation using truth and link sets but this approach is very similar to locating common exclusions when avoiding overlapping Deadly Patterns.