Sept 8th killer

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Sept 8th killer

Postby Guest » Sat Sep 10, 2005 7:53 pm

Can someone explain the logic to this puzzle (the killer one).
http://www.timesonline.co.uk/article/0,,18209-1769363,00.html

I understand that 1-5 are in c5 r3-r7 so
r2c5 has to be 6 r2c6 has to be 1
r8c5has to be 7 r8c4 has to be 1
and 16 in row 5 has to be 7 and 9
and r1c5 can be 8 or 9
and r9c5 can be 8 or 9
r1c3 has to be 1 cause you either have 3 or 4 left to make 12

I finished this puzzle but only by trial and error.... well actually after messing up about 5 tiimes I just looked what numbers I had on all 5 papers and started with them. This seemed way harder than even the 'deadly' example sudoku.

thanks for any help
Guest
 
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Joined: 25 November 2005

Re: Sept 8th killer

Postby whohe » Sat Sep 10, 2005 11:12 pm

kylek wrote:Can someone explain the logic to this puzzle (the killer one).
http://www.timesonline.co.uk/article/0,,18209-1769363,00.html

I understand that 1-5 are in c5 r3-r7 so
r2c5 has to be 6 r2c6 has to be 1
r8c5has to be 7 r8c4 has to be 1
and 16 in row 5 has to be 7 and 9
and r1c5 can be 8 or 9
and r9c5 can be 8 or 9
r1c3 has to be 1 cause you either have 3 or 4 left to make 12

I finished this puzzle but only by trial and error.... well actually after messing up about 5 tiimes I just looked what numbers I had on all 5 papers and started with them. This seemed way harder than even the 'deadly' example sudoku.

thanks for any help


If my memory serves me right, think about the 24 (starting R8C3) and the 23 (R1C6) as your next step. After that the block sum=45 can be used on the top right and bottom left blocks.
whohe
 
Posts: 32
Joined: 28 May 2005


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