Hi all,
I would like to point out that for a while now your comments have nothing to do with my thread!
Maybe you should open a thread called "I'm trying to understand the whips".
Robert
eleven wrote:denis_berthier wrote:eleven wrote:Now i look at the link r9c8{n4 n1} - r9c2{n1 n2}. Why not 9 ?
9 where? A link is a link. There's no 9 in it.
If you mean why not 9 in r9c2{n1 n2}, it's obvious: because n9r9c2 is a z-candidate (linked to the target n9r1c2.
Ok, and r9c8{n4 n1} is a valid link, because 7 is a z-candidate (?) from the first link r1n7{c2 c8}, and c7n2{r9 .} is an impossible link, because in the 3rd link b3n6{r1c7 r2c7} 6 is a ?-candidate in r2c7. Have i got it ?
+----------------+----------------+----------------+
! 2 179 39 ! 3569 8 359 ! 16 167 4 !
! 47 5 489 ! 469 1 249 ! 268 3 278 !
! 134 18 6 ! 349 7 234 ! 5 9 128 !
+----------------+----------------+----------------+
! 356 268 2358 ! 1 49 7 ! 348 45 389 !
! 9 4 1 ! 58 3 58 ! 7 2 6 !
! 357 78 358 ! 2 49 6 ! 1348 145 1389 !
+----------------+----------------+----------------+
! 146 126 7 ! 348 5 1348 ! 9 146 123 !
! 1456 3 459 ! 479 2 149 ! 146 8 17 !
! 8 129 249 ! 3479 6 1349 ! 1234 147 5 !
+----------------+----------------+----------------+
whip[7]: r1n7{c2 c8} - r1n1{c8 c7} - b3n6{r1c7 r2c7} - r8c7{n6 n4} - r9c8{n4 n1} - r9c2{n1 n2} - c7n2{r9 .} ==> r1c2≠9
eleven wrote:Back to Robert's puzzle then.
Denis, how would you make the elimination -1r13c7 in the first step ?
(init "..6....9..75.2.8..9...7...2.3...74.....245.....46...7.8...6...3..1.3.54..4....7..")
(try-to-eliminate 167)
(try-to-eliminate 177)
z-chain[3]: b6n2{r6c7 r4c8} - r7c8{n2 n1} - b3n1{r2c8 .} ==> r6c7≠1
with z-candidates = n1r3c7 n1r1c7
whip[10]: r1c7{n1 n3} - r3c7{n3 n6} - b3n1{r3c7 r2c8} - b1n1{r2c1 r3c2} - r3n8{c2 c3} - r3n3{c3 c4} - c4n4{r3 r7} - r7n7{c4 c3} - r5c3{n7 n9} - r5c7{n9 .} ==> r7c7≠1
eleven wrote:Well, as you could see, i have no problems to translate Robert's chain into my usual way of writing chains (so it could be by myself), while your way is very different. I guess the reason is, that we are both manual solvers.
Nevertheless you claimed, he had something copied from you, didn't you ?
a) 9r1c2 => -1r1c2,-7r1c2;-9r9c2 missing
b) 7r1c8 => -1r1c8 ;-6r1c8 ;-1r8c7;-7r9c8 r1n7{c2 c8}
c)(-1r1c2,-1r1c8) 1r1c7=>-6r1c7 r1n1{c8 c7}
d)(-6r1c8,-6r1c7) 6r2c7=>-6r8c7 ;-2r2c7 b3n6{r1c7 r2c7}
e)(-1r8c7,-6r8c7)4r8c7=>-4r9c8 r8c7{n6 n4}
f)(-4r9c8 ;-7r9c8)1r9c8=>-1r9c2 r9c8{n4 n1}
g)(-1r9c2 ;-9r9c2)2r9c2=>-2r9c7 r9c2{n1 n2}
and now the last pieces of the whip - c7n2{r9 .} ==> r1c2≠9
Clearly we have no “2” in the column 7
eleven wrote:yes i know, that you can't understand that. So please don't claim again, that Robert copied anything from you. We never needed yor strange solving theory.
champagne wrote:Why is the start missing??? I don't know.
If there is another logic for the whip without the start, I don't understand it.
champagne wrote:And for me, unless you have the chance to have groups, such sequences are not reversible contrary to the AIC's and AIC's nets.
denis_berthier wrote:champagne wrote:Why is the start missing??? I don't know.
If there is another logic for the whip without the start, I don't understand it.
The start is not missing. If you had read the definitions instead of typing on your keyboard faster than your brain, you'd know that the target is written at the end.
champagne wrote:denis_berthier wrote:champagne wrote:Why is the start missing??? I don't know.
If there is another logic for the whip without the start, I don't understand it.
The start is not missing. If you had read the definitions instead of typing on your keyboard faster than your brain, you'd know that the target is written at the end.
in another words, if you can make if difficult, why should you make it easy
denis_berthier wrote:Yesss, that's exactly what I meant. I understand that reading a definition before talking of what you don't understand is much harder than typing random remarks on a keyboard.