now corrected
Rainbow as in "All the numbers in the rainbow"
The numbers are from 0-9
It is AntiSymmetric so the numbers are in pairs and they are positioned symmetrically.
There is a zero in every nonet, row and column.
Each other number is missing from one and only one nonet, row and column.
This means that the nonet where a missing number row and the column with the same number missing cross, has that same number missing. I know this by checking examples but cannot see how to prove it.
The clues are Sindoku
The clues are based on singletons i.e. a number with no adjacent numbers.
The clues at the corners refer to the four adjacent cells
If one number is given it is a singleton and the other three numbers are consecutive.
If two numbers are given they are singletons and the other two numbers are consecutive.
If the corner is blue all four numbers are singletons.
If the corner is pink there are two pairs of consecutive numbers.
If the corner is red there are four consecutive numbers.
if the corner is green there is a repeat number or perhaps two.
If no information is given at a corner nothing is implied.
I forgot to remind you that in all my puzzles 0 is consecutive to 9.
Rainbow AS Sin 3
Nice and easy as a starter
I think it solves without AntiSymmetry.
Rainbow AS Sin 3H
Sindoku: all the coloured clues are given. I used this heavily in my solution.
Very hard
