Hi P.O.,
The puzzle does not have a bivalue cell in rc, but does in rn and cn, for example 5r2c45.
The following (TDP) track (where "->" indicates the order of construction) shows that 5r2c5 can be eliminated, while 5r2c4 is a simple backdoor.
P(5r2c5) : [ 5r2c5->1r2c2->1r5c1->( 5r6c1->5r4c7->1r9c7->1r7c6 )->5r5c6->6r45C4 ]->8r2c4->48b3->7r13c7->7r6c9->3r5c9->3r1c3->3r8c4->7r7c4->... => 5r7 empty => r2c5≠5 => r2c4=5, stte.
It is also possible to solve with a set of two tracks, the interactions are enough to find the solution without finding contradiction as before, like this:
P(5r2c5) : [ 5r2c5->1r2c2->1r5c1->( 5r6c1->5r4c7->1r9c7->1r7c6 )->5r5c6->6r45C4 ]->8r2c4->48b3->7r13c7->
7r6c9->...
P(5r2c4) : 5r2c4->5r7c6->1r7c8->1r4c7->5r6c7->
7r6c9->...
=> r6c9=7, stte
Robert