Let k be the digit present in R5C5
The cells opposite to the cells containing that digit k, contain each digit uniquely
(Note that the opposite cell of RiCj is R(10-i)C(10-j).)
An easy puzzle:
- Code: Select all
..2|.5.|4..
9..|6..|1..
8.4|27.|...
---+---+---
...|..6|.85
...|...|9..
.7.|4..|.6.
---+---+---
..1|.2.|...
...|...|3.9
.6.|...|...
More difficult and possibly chains:
- Code: Select all
258|...|..9
...|...|.7.
7..|...|...
---+---+---
.2.|..9|...
...|6.4|1..
8..|.5.|...
---+---+---
..9|53.|6..
...|...|.8.
1..|.98|...