November 14, 2019

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November 14, 2019

Postby ArkieTech » Thu Nov 14, 2019 11:49 am

Code: Select all
 *-----------*
 |...|.8.|...|
 |..9|7.1|2..|
 |.6.|...|.8.|
 |---+---+---|
 |1..|...|..2|
 |.3.|...|.5.|
 |..7|3.6|1..|
 |---+---+---|
 |.5.|.9.|.6.|
 |4..|.7.|..8|
 |...|...|...|
 *-----------*

....8......97.12...6.....8.1.......2.3.....5...73.61...5..9..6.4...7...8.........



Play/Print this puzzle online
dan
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Re: November 14, 2019

Postby StrmCkr » Thu Nov 14, 2019 12:02 pm

Code: Select all
+-------------------+--------------------------+-------------------------+
| 2357  1247  12345 | 24569    8       23459   | 345679  13479   1345679 |
| 358   (48)  9     | 7        356-4   1       | 2       34      3456    |
| 2357  6     12345 | 2459     2345    23459   | 34579   8       134579  |
+-------------------+--------------------------+-------------------------+
| 1     9-4   456   | 4589     (45)    45789   | 3678    37      2       |
| 69    3     46(2) | 1489(2)  14(2)   4789(2) | 678     5       67      |
| 258   (28)  7     | 3        (25)    6       | 1       49      49      |
+-------------------+--------------------------+-------------------------+
| 237   5     1238  | 1248     9       2348    | 347     6       1347    |
| 4     129   1236  | 1256     7       235     | 359     1239    8       |
| 69    1279  12368 | 124568   123456  23458   | 34579   123479  134579  |
+-------------------+--------------------------+-------------------------+

AlS-W-Wing
ALS A = 248 @ R26C2
AlS B = 245 @ R46C5
strong link (2) R5C3 = R5C456 (2)
=> R4C2,R2C5 <> 2
singles to the end.
Some do, some teach, the rest look it up.
stormdoku
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Re: November 14, 2019

Postby Mauriès Robert » Thu Nov 14, 2019 1:44 pm

Hi ArkieTech and StrmCkr,

This puzzle is easy. Here is a resolution by the TDP (See here).

P(5r4c3)∩P(5r6c1)={8r5c7, 4r5c3, 9r4c3, ...} which are puzzle solutions. The puzzle then ends the basic techniques (TB).

Hidden Text: Show
Image


Sincerely
Robert
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Re: November 14, 2019

Postby Ngisa » Thu Nov 14, 2019 3:20 pm

Code: Select all
+----------------------+-------------------------+---------------------------+
|  2357   1247   12345 | 24569    8        23459 | 345679   13479    1345679 |
|  358    8-4    9     | 7        3456     1     | 2       a34       3456    |
|  2357   6      12345 | 2459     2345     23459 | 34579    8        134579  |
+----------------------+-------------------------+---------------------------+
|  1     e49     456   | 4589     45       45789 | 3678    a37       2       |
|ec269    3      246   | 12489    124      24789 | 678      5       b67      |
|  258    28     7     | 3        25       6     | 1        49       49      |
+----------------------+-------------------------+---------------------------+
|  237    5      1238  | 1248     9        2348  | 347      6        1347    |
|  4      129    1236  | 1256     7        235   | 359      1239     8       |
| d23679  1279   12368 | 124568   123456   23458 | 34579    123479   134579  |
+----------------------+-------------------------+---------------------------+

(4=37)r24c8 - (7=6)r5c9 - r5c1 = (6-9)r9c1 = (94)b4p42 => - 4r2c2; stte

Clement
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Re: November 14, 2019

Postby SteveG48 » Thu Nov 14, 2019 4:41 pm

Code: Select all
 *--------------------------------------------------------------------------------------*
 | 2357     1247     12345    | 24569    8        23459    | 345679   13479    1345679  |
 | 358     d48       9        | 7        3456     1        | 2        34       3456     |
 | 2357     6        12345    | 2459     2345     23459    | 34579    8        134579   |
 *----------------------------+----------------------------+----------------------------|
 | 1       b9-4    ab456      |a4589   ab45      a45789    | 3678     37       2        |
 | 69       3       c246      | 12489    124      24789    | 678      5        67       |
 | 258     c28       7        | 3        25       6        | 1        49       49       |
 *----------------------------+----------------------------+----------------------------|
 | 237      5        1238     | 1248     9        2348     | 347      6        1347     |
 | 4        129      1236     | 1256     7        235      | 359      1239     8        |
 | 69       1279     12368    | 124568   123456   23458    | 34579    123479   134579   |
 *--------------------------------------------------------------------------------------*


4r4c3456 = (56)r4c35&4r4c2 - (4|6=28)b4p68 - (8=4)r2c2 => -4 r4c2 ; stte
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Re: November 14, 2019

Postby eleven » Thu Nov 14, 2019 7:29 pm

Mauriès Robert wrote:This puzzle is easy. Here is a resolution by the TDP (See here).

P(5r4c3)∩P(5r6c1)={8r5c7, 4r5c3, 9r4c3, ...} which are puzzle solutions. The puzzle then ends the basic techniques (TB).

You take a sledgehammer to crack a nut, and call it easy.
Just 4 bivalue cells (r26c2,r46c5) are needed to solve it.
No need to develop 2 nets.
Code: Select all
 *------------------------------------------------------------------------------------*
 |  2357   1247   12345   |  24569    8        23459   |  345679   13479    1345679   |
 |  358   #48     9       |  7        356-4    1       |  2        34       3456      |
 |  2357   6      12345   |  2459     2345     23459   |  34579    8        134579    |
 |------------------------+----------------------------+------------------------------|
 |  1      9-4    456     |  4589    #45       45789   |  3678     37       2         |
 |  69     3      246     |  12489    124      24789   |  678      5        67        |
 |  258   #28     7       |  3       #25       6       |  1        49       49        |
 |------------------------+----------------------------+------------------------------|
 |  237    5      1238    |  1248     9        2348    |  347      6        1347      |
 |  4      129    1236    |  1256     7        235     |  359      1239     8         |
 |  69     1279   12368   |  124568   123456   23458   |  34579    123479   134579    |
 *------------------------------------------------------------------------------------*
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Re: November 14, 2019

Postby SpAce » Thu Nov 14, 2019 9:07 pm

Here's another sledgehammer for you, eleven :D

gem.png
gem.png (82.28 KiB) Viewed 552 times

(6|7)r5c9 => +8 r2c2, -4 r1c7,r2c5, -45 r4c6; stte

Or:

(6)r5c9 -> (empty)r5c3 => -6 r5c9; stte

Or:

(6)r5c9 -> (2x5)b5 => -6 r5c9; stte

--
Why do we even bother writing chains and stuff when we could just do this and call it easy? Funny that I never realized it before.
-SpAce-: Show
Code: Select all
   *             |    |               |    |    *
        *        |=()=|    /  _  \    |=()=|               *
            *    |    |   |-=( )=-|   |    |      *
     *                     \  ¯  /                   *   

"If one is to understand the great mystery, one must study all its aspects, not just the dogmatic narrow view of the Jedi."
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Re: November 14, 2019

Postby eleven » Thu Nov 14, 2019 9:37 pm

Oh, how colorful it can be.
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Re: November 14, 2019

Postby SpAce » Thu Nov 14, 2019 9:58 pm

eleven wrote:Oh, how colorful it can be.

I knew you'd love it! :D One more for the road then...

gem2.png
gem2.png (76.65 KiB) Viewed 548 times

(5)r6c15 => -4 r13c3,r4c2,r5c6, -45 r2c5, -6r45c3; stte

Or:

(5)r6c1 -> (empty)r5c1 => +4 r4c5,r5c3, +5 r4c3,r6c5; stte
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Re: November 14, 2019

Postby Mauriès Robert » Fri Nov 15, 2019 11:30 am

eleven wrote:You take a sledgehammer to crack a nut, and call it easy.
Just 4 bivalue cells (r26c2,r46c5) are needed to solve it.
No need to develop 2 nets.


Yes Eleven, we can also do P(2r6c5) ∩ P(5r6c5)={9r4c2, ...} solution and end. But it was too easy ! (humor ;) ).
Sincerely
Robert
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