
I'm just getting into some of the advanced solving techniques and I now understand (and have used) Swordfish

000700530796005001000002000000000010074000000003870005020010607000000380030069000
150000000009060023000090650000170000040030070008500040801000009000002000003000800
030006050609000000000200000050019003901670500000000000005004020108000000790800601
809000200000000030340501000900000050400006000002038600200090000000200800058000004
008030000000607010000000200000045803000072409090000070020004005053080940000000300
004320000000800200010006005000000000008000009900078400001000704072009300000052100
000000750100000000306098000000000403503046000021000000804000007000005002002079804
400030706090004002010000008000007900002000060080003057008000000070020001000071040
000041000420000086000000590000005000006000830103906005068100070000070000200000060
moggymidge wrote:".. but I'm having trouble with using 'colours.."'
yasmin wrote:I have one more question re. em's reply:
QUOTE:
" The thing about colouring is that it allows you to draw conclusions about what you can eliminate -
if two of the same colour are in the same group then all cells of that colour are false "
What I don't get is this: how can you say that all cells of that colour are categorically false?
. . . | a . . | . A .
. . . | . . . | . . .
. . . | . . A | a . .
-------+-------+------
. . . | . . . | . . .
. . . | . . . | . . .
. . . | . . . | . . .
-------+-------+------
. . . | . . . | . . .
. . . | a . . | A . .
. . . | x . a | . a .
yasmin wrote:Sure, we can't have 2 true ones and 1 false, but the opposite IS possible, or am I not getting something?
vidarino wrote:"...Here is a color map from a puzzle posted in another forum a few minutes ago .."
vidarino wrote:Ergo,..."
vidarino wrote:"..A must be the true colour.."