yasmin wrote:I have one more question re. em's reply:
QUOTE:
" The thing about colouring is that it allows you to draw conclusions about what you can eliminate -
if two of the same colour are in the same group then all cells of that colour are false "
What I don't get is this: how can you say that all cells of that colour are categorically false?
I'll answer that with an example. Here is a color map from a puzzle posted in another forum a few minutes ago;
- Code: Select all
. . . | a . . | . A .
. . . | . . . | . . .
. . . | . . A | a . .
-------+-------+------
. . . | . . . | . . .
. . . | . . . | . . .
. . . | . . . | . . .
-------+-------+------
. . . | . . . | . . .
. . . | a . . | A . .
. . . | x . a | . a .
Looking at the top row, for example, we know that exactly one of A or a is true, since they are conjugates. Continuing coloring conjugates in rows, columns and boxes we end up with an interesting situation in box 8; we get two a's. This means that if a was the true color, we would have a contradiction by having two 8s in one box. Ergo, A must be the true color.
Hope that clarified things a bit.
Vidar