After Champagne's post I suppose I should post some interim findings based on only a few JE3+SK puzzles
So far the 3 base digits always occur as givens in the 4 SK Loop boxes, with a 4th given that's resolvable to two conjugate configurations. Using that digit as a way to navigate around the boxes then always provides a simple way to solve the puzzle, but usually needs a few steps.
Some nice shortcuts using the JE inferences are sometimes available though as here:
98.7.....6.....5....5.4..7..7..3...2..94..6.......1.8...65..4......8..1......2..3 JE3+SK #006
After basic and SK loop eliminations
- Code: Select all
*----------------------*----------------------*----------------------*
| <9> <8> 123 | <7> 56-12 5-3 | #123 2346 14 |
| <6> 4 7 | #123-8 129 389 | <5> 239 189 |
| #123 #123 <5> | 1238 <4> 69 | 1238 <7> 69 |
*----------------------*----------------------*----------------------*
| 1458 <7> 148 | 689 <3> 569 | 19 459 <2> |
| 1238 123 <9> | <4> 257 578 | <6> 35 157 |
| 2345 6 234 | 29 579 <1> | 379 <8> 4579 |
*----------------------*----------------------*----------------------*
| 1238 123 <6> | <5> 179 379 | <4> 29 789 |
| 237 59 23 | 369 <8> 4 | 279 <1> 56 |
| 1478 59 148 | 19 679 <2> | 789 56 <3> |
*----------------------*----------------------*----------------------*
(123)JE3:r3c12,r1c7,r2c4 => r2c4 <> 8
(x)r1c3 = (x)r3c12 – (x)r3c47 =[JE]= (x)r1c7,r2c4 => r1c5 <> 12, r1c6 <> 3
sste
ie either a digits is in r1c3 or the base cells and hence one of the two targets, so can be eliminated from cells seen by the targets & r1c3.
The term "basic eliminations" has never been properly defined AFAIK but here means tuples up to size 3, box/line eliminations & simple fish of any size.