Luke wrote:The long answer, since I'm stuck here holding purses while the girls Xmas shop:
Okay Luke, I'm not getting this: Since when do women leave their purses behind to go shopping?
Luke wrote:The long answer, since I'm stuck here holding purses while the girls Xmas shop:
DonM wrote:Luke wrote:The long answer, since I'm stuck here holding purses while the girls Xmas shop:
Okay Luke, I'm not getting this: Since when do women leave their purses behind to go shopping?
Luke wrote:DonM wrote:Luke wrote:The long answer, since I'm stuck here holding purses while the girls Xmas shop:
Okay Luke, I'm not getting this: Since when do women leave their purses behind to go shopping?
You kiddin me? Read it n weep
*-----------------------*-----------------------*-----------------------*
| 16 3 45 | 46 2456 259 a | 8 19 b 7 |
| 16 d 2 57 | 8 56 e 579 | 19 c 4 3 |
| 9 8 47 | 347 34 1 | 6 2 5 |
*-----------------------*-----------------------*-----------------------*
| 4 1 3 | 2 9 6 | 7 5 8 |
| 8 5 9 | 137 13 37 | 4 6 2 |
| 7 6 2 | 5 8 4 | 3 19 19 |
*-----------------------*-----------------------*-----------------------*
| 5 4 1 | 9 7 8 | 2 3 6 |
| 3 9 8 | 146 12456 25 e | 15 d 7 14 |
| 2 7 6 | 134 1345 35 | 159 8 149 |
*-----------------------*-----------------------*-----------------------*
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1#2=65)r2c1,r8c7 - (65=52)r2c5,r8c6 => r1c6 <> 25 stte
+---------------+---------------------+---------------+
| 16 3 (45) | (46) 2456 259 | 8 19 7 |
| 16 2 (+7-5) | 8 (56) (59-7) | (19) 4 3 |
| 9 8 47 | 347 34 1 | 6 2 5 |
+---------------+---------------------+---------------+
| 4 1 3 | 2 9 6 | 7 5 8 |
| 8 5 9 | 137 13 37 | 4 6 2 |
| 7 6 2 | 5 8 4 | 3 19 19 |
+---------------+---------------------+---------------+
| 5 4 1 | 9 7 8 | 2 3 6 |
| 3 9 8 | 146 12456 (+2-5) | (15) 7 14 |
| 2 7 6 | 134 1345 35 | 159 8 149 |
+---------------+---------------------+---------------+
When the shared chain segment is short (two strong inferences, in this case), I don't see the merger as simpler than expressing the two chains separately.David P Bird wrote:My disciplines don't allow kraken nodes but do allow split nodes in desperate situations, so here I can merge two chains into one to produce a one-stepper.
- Code: Select all
*-----------------------*-----------------------*-----------------------*
| 16 3 45 | 46 2456 259 a | 8 19 b 7 |
| 16 d 2 57 | 8 56 e 579 | 19 c 4 3 |
| 9 8 47 | 347 34 1 | 6 2 5 |
*-----------------------*-----------------------*-----------------------*
| 4 1 3 | 2 9 6 | 7 5 8 |
| 8 5 9 | 137 13 37 | 4 6 2 |
| 7 6 2 | 5 8 4 | 3 19 19 |
*-----------------------*-----------------------*-----------------------*
| 5 4 1 | 9 7 8 | 2 3 6 |
| 3 9 8 | 146 12456 25 e | 15 d 7 14 |
| 2 7 6 | 134 1345 35 | 159 8 149 |
*-----------------------*-----------------------*-----------------------*
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1#2=65)r2c1,r8c7 - (65=52)r2c5,r8c6 => r1c6 <> 25 stte
ronk wrote:When the shared chain segment is short (two strong inferences, in this case), I don't see the merger as simpler than expressing the two chains separately.
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1=6)r2c1 - (6=5)r2c5 => r1c6<>5
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1=5)r8c7 - (5=2)r8c6 => r1c6<>2 stte
It might allow someone to claim they solved the puzzle with a single step, as you did, but I challenge that claim as well.
ronk wrote:When the shared chain segment is short (two strong inferences, in this case), I don't see the merger as simpler than expressing the two chains separately.
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1=6)r2c1 - (6=5)r2c5 => r1c6<>5
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1=5)r8c7 - (5=2)r8c6 => r1c6<>2 stte
It might allow someone to claim they solved the puzzle with a single step, as you did, but I challenge that claim as well.
+-----------------------------------------------------------------------+
| 16 3 45 | 46 2456 259 | 8 19 7 |
| 16 2 57 | 8 56 579 | 19 4 3 |
| 9 8 47 | 347 34 1 | 6 2 5 |
|-----------------------+-----------------------+-----------------------|
| 4 1 3 | 2 9 6 | 7 5 8 |
| 8 5 9 | 137 13 37 | 4 6 2 |
| 7 6 2 | 5 8 4 | 3 19 19 |
|-----------------------+-----------------------+-----------------------|
| 5 4 1 | 9 7 8 | 2 3 6 |
| 3 9 8 | 146 12456 25 | 15 7 14 |
| 2 7 6 | 134 1345 35 | 159 8 149 |
+-----------------------------------------------------------------------+
# 44 eliminations remain
(9*)r1c6=r1c8-(9=165)r2c715-(*95=2)r1c6-(2=5)r8c6-(5=1)r8c7-(1=9)r2c7-r1c8=(9)r1c6
daj95376 wrote:Hmmm. The way I see it, your two chains can form a network representation of a discontinuous loop. And thus qualify as a single-stepper. However, I'm not a fan of DPB's representation of the network.
I am not a fan of the current trend of making networks look like chains. However, I have succumbed in my own posts of late because of the convenience of using memory to portray secondary eliminations (from networks) as part of a psudo-chain structure.
In addition, I believe that the definition of AIC should be altered to allow the initial (false) assumption to be (selectively) carried forward in its own cell(s). The following would then be an acceptable AIC "discontinuous loop" (using a lasso).
daj95376 wrote:
- Code: Select all
+-----------------------------------------------------------------------+
| 16 3 45 | 46 2456 259 | 8 19 7 |
| 16 2 57 | 8 56 579 | 19 4 3 |
| 9 8 47 | 347 34 1 | 6 2 5 |
|-----------------------+-----------------------+-----------------------|
| 4 1 3 | 2 9 6 | 7 5 8 |
| 8 5 9 | 137 13 37 | 4 6 2 |
| 7 6 2 | 5 8 4 | 3 19 19 |
|-----------------------+-----------------------+-----------------------|
| 5 4 1 | 9 7 8 | 2 3 6 |
| 3 9 8 | 146 12456 25 | 15 7 14 |
| 2 7 6 | 134 1345 35 | 159 8 149 |
+-----------------------------------------------------------------------+
# 44 eliminations remain
(9*)r1c6=r1c8-(9=165)r2c715-(*95=2)r1c6-(2=5)r8c6-(5=1)r8c7-(1=9)r2c7-r1c8=(9)r1c6
SteveG48 wrote:ronk wrote:When the shared chain segment is short (two strong inferences, in this case), I don't see the merger as simpler than expressing the two chains separately.
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1=6)r2c1 - (6=5)r2c5 => r1c6<>5
(9)r1c6 = (9)r1c8 - (9=1)r2c7 - (1=5)r8c7 - (5=2)r8c6 => r1c6<>2 stte
It might allow someone to claim they solved the puzzle with a single step, as you did, but I challenge that claim as well.
Hmm. I think it qualifies as a single step. A single assumption, that r1c6 is not a 9, leads to the conclusion that it is neither a 5 nor a 2 as well, a contradiction. That seems as much a single step as the Kraken argument, which comes down to 3 parallel chains, all leading to the same conclusion and comprising all of the possibilities.
DonM wrote:There is a major semantics problem going on here and it has to do with the term 'single-stepper'. It would seem to me that a chain that starts off with a single assumption (eg. if not (9)r1c6) and follows a straight inference path to an exclusion or exclusions by continuity or discontinuity that solves the puzzle was the original (and correct) perception of a 'single-stepper'.