I'm with Ronk
Terak is makig what seems like an odd distinction. Heres the puzzle, filtered for 8s for clarity:
Figure A
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*-----------------------------------------------*
|-8 . . | . -8 . | 8 . . |
| . 8 . | . . . | . . 8 |
| . 8 . | . . +8 | 8 . . |
|---------------+---------------+---------------|
|+8 . . | . . -8 | . . . |
| . . . | . . . | 8 . 8 |
| . . -8 | . +8 . | . . . |
|---------------+---------------+---------------|
| . 8 8 | . . . | . 8 . |
| . . . | 8 . . | . . . |
| . . 8 | . . . | . 8 . |
*-----------------------------------------------*
No other 8s are conjugates with these 7. Because two 8s have the same symbol in the top row, we know that the PLUS signs are 8s and the MINUS signs are not. Your claim is that this is a contradiction -- a claim which I do not agree -- but I wont argue that point. Instead, take a look a the following grid which has one change in brackets:
Figure B
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*-----------------------------------------------*
| 8 . . | . -8 . | 8 . . |
| . 8 . | . . . | . . 8 |
| . 8 . | . . +8 | 8 . . |
|---------------+---------------+---------------|
|+8 . . | . . -8 | . . . |
| . . . | . . . | 8 . 8 |
| . . -8 | . +8 . | . . . |
|---------------+---------------+---------------|
| . 8 8 | . . . | . 8 . |
| . . . | 8 . . | . . . |
|[8] . 8 | . . . | . 8 . |
*-----------------------------------------------*
Because of the additional 8 at r9c1, the 8 at r1c1 cannot be labeled. We can still eliminate 8 from this cell, as it can see cells of both signs. Suddenly, this deduction is fair and clearly requires no contradiction.
In Figure A, the solver is free to refrain from labeling r1c1 and simple excude it once r1c5 and r4c1 are fixed. This is always the case. Just as you update your candidates after entering a digit, you could make exclusions as soon they become available and then continue coloring. You never need to label two cells in one group with the same color. However, it's much easier to show it that way when posting a solution.
The distinction between contradition and other types of deduction is arbitrary:
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We could say:
R1c1=1 -> r2c1=3 -> r2c2=4
R1c1=2 -> r1c2=3 -> r2c2=4
Therefore r2c2=4
and call it a forcing chain
Or we could say:
R2c2=3 -> r1c2=2 -> r1c1=1
R2c2=3 -> r2c1=1 -> r1c1=2
Therefore, r2c2<>3
and call it a proof by contradiction
Or we could say:
Thats an xy-wing -- r2c2 cannot be 3.
Coloring is not the pattern -- it is an efficient *method* for finding a *pattern*. I dont see why we would handicap ourselves.