Thanks,
blue, for the amazing morph!
And you only needed five “minor” tweeks to get from my finned 1-Fish network to your full [b7]SIS solution.
Well, just for the record, I counted five separate paths in the original fin network:
- Code: Select all
r3c3-r46c3...r5c1-r5c4...----r8c9
r3c3-r46c3...r5c1-r79c1...---r8c9
r3c3-r3c9...r5c1-r5c4...-----r8c9
r3c3-r3c9...r5c1-r79c1...----r8c9
r3c3-r7c3...-----------------r8c9
The strong\weak links total up to:
15x20 c44b3344446677777\r3355668888899c1133388
Then add in the unfinned 1x1 Fish r3\c9, which removes r3\r3, to get:
15x20 c44b3344446677777\r355668888899c11333889
The target cell has six excess covers to effect the elimination, but r8c8 has seven, so it would go, too. Plus the logic has “base triplets” (and worse) in b4 and b7, which would have to be covered and thus increase the overall k-rank. IOW, this logic is a hopeless mess. I did try some of
Obi's conversion arithmetic to reduce the size, but doing that only made my head hurt more.
So, it would appear that the 1x1 Fish plus fin network is certainly valid, but then why doesn't it convert directly to an Obi-Fish?
Edit to add:
OK, I wasn't getting anywhere either with that original r3c3 fin network, but it sure took me a lot longer to realize why. Those
diverging weak links were the problem, where I kept adding in an extra b7 or b4 base sector for every new weak leak entering a SIS. The mirror-image network, as
blue noted early on with its
converging weak links, makes it much easier to identify the proper pathways and to correctly count the SIS-related base sectors.
I would add only that whenever redundant base\cover sectors appear (r3\r3, e.g.)
Obi's arithmetic does allow one to simply subtract that sector from both sides of the Fish. So, one can actually finish this analysis early with
blue's network below:
- Code: Select all
r46c3--------------------
|| \
r6c2-r6c7=r45c8-r2c8=r3c9 - r3c3=r3c9 - r8c9
|| / /
r9c2-r9c4=r5c4-r5c1 / /
|| / / /
r79c1-------- / /
|| / /
r7c3-------------------------------- /
|| /
r8c2------------------------------------------
Paths containing the “r3c9-r3c3=r3c9” section have the redundant r3\r3 contributions, which are then subtracted out in the final Obi-Fish. However, it does remain rather impressive that
blue can further manipulate these network diagrams to avoid that final subtraction.