eleven wrote:SpAce, a proof is NOT, if somebody sees a link in the way you want, but if no other interpretation is possible.
But when i looked at the link at the first time, i already had another interpretation:
If r3c6,r7c9 is not 3,8, then it can be 3,3, and no 3 is possible in b8p26. So there is no strong link. dot.
That's enough to show, that it is not proved without writing out the links you use.
Same, if both are 8, then there can:t be an 8 in b8p26.
So the conclusion is, that the writer of the (poor) link only looked at one of 3 possibilities ...
So, apparently your argument hasn't changed at all since we had the original discussion. In other words, you totally ignored my extensive
counterarguments to it. Why should I pay any attention to yours then?
To avoid jumping between threads, here's my original solution for reference:
SpAce wrote:- Code: Select all
.------------.------------------.----------------.
| 7 59 25 | 4 238 1 | 38 6 389 |
| 3 1 8 | 9 7 6 | 4 5 2 |
| 4 69 26 | 5 238 ac38* | 1 7 9-38 |
:------------+------------------+----------------:
| 8 4 1 | 3 9 5 | 7 2 6 |
| 5 2 3 | 6 1 7 | 9 8 4 |
| 6 7 9 | 8 4 2 | 5 3 1 |
:------------+------------------+----------------:
| 1 356 56 | 7 bc38#6* 9 | 2 4 ac38* |
| 2 36 4 | 1 5 bc38* | 368 9 7 |
| 9 8 7 | 2 36 4 | 36 1 5 |
'------------'------------------'----------------'
(3,8)r3c6,r7c9 = (38-6)b8p26 = RP(38)r38c6,r7c59 => -38 r3c9; stte
Let's forget that short version for a second and look at the more explicit one I offered:
eleven wrote:SpAce wrote:(3,8)r3c6,r7c9 = (3,8)b8p62|(8,3)b8p26 - 6b8p2 = RP(38)r38c6,r7c59
You agree with that, I hope?
No, if i look at the 4 cells, and
r3c6,r7c9 is not 3,8, but 3,3, then b8p6 is 8 and b8p2 is 6.
Does eleven's argument (same as now) make any sense, considering what's written in my chain? Only the left side of the first strong link has the cells r3c6,r7c9. The right side has b8p26 i.e. r7c5,r8c6. Thus it should be pretty obvious that bilocal strong links (+ implicit logic) are used to build the combo strong link. No possible cases are missing from that, as far as I see.
Why would I worry about any alternate digit combos in r3c6,r7c9? My logic is not using them, and it should be obvious from the way it's written. To me eleven's argument is like saying that someone's use of UR externals is invalid if there's some contradicting logic available with the internals. It's ignoring the fact that both sets are valid SIS on their own. What am I missing?
Let's break it down so you can tell me where it's actually ambiguous.
1. Do you agree that:
(3,8)r3c6,r7c9 <-> (3r3c6 & 8r7c9)
(3r3c6 & 8r7c9) = (3r8c6 | 8r7c5)
2. Do you agree that:
3r3c6 = (3-8)r8c6 = 8r7c5
8r7c9 = 8r7c5 - (8=3)r8c6
3. Do you agree that we can (and routinely do) write them (2) as:
3r3c6 = (3,8)b8p62
8r7c9 = (8,3)b8p26
4. Do you agree that (based on 1 and 3):
(3r3c6 & 8r7c9) = (3,8)b8p62|(8,3)b8p26
=>
(3,8)r3c6,r7c9 = (3,8)b8p62|(8,3)b8p26
? If so, you should accept the explicit version. If not, tell me where the error is.
5. Do you agree that:
(3,8)b8p62 <-> (8,3)b8p26
=>
(3,8)r3c6,r7c9 = (3,8)b8p62
? If so, we're pretty close to the short version. I'd be fine leaving it like that if it's easier to read. The original without the latter comma takes a bit more mental acrobatics to see why the strong link is valid.
SpAce wrote:My link does not depend on any external logic whatsoever.
eleven wrote:This is wrong. It uses the link 8b8p6 = 8b8p2, which is not written out (and if there were another 8 in the box - in a cell not included in the link, it would always be wrong).
mith wrote:eleven is correct that it relies on 8b8p6 = 8b8p2 in both cases. (I just viewed this as a hidden single, but it does rely on no 8 candidate elsewhere in the box, which is looking at another cell.)
That is a pretty weird interpretation of external logic. Of course every bilocal link depends on candidates
missing in the other cells of the relevant house. If they're counted as part of the logic, then missing digits in bivalue strong links should be counted too. Absurd, no?