## where from here?

Everything about Sudoku that doesn't fit in one of the other sections

### where from here?

I've solved this one but it was a pure guess. Tried one option supposing that 4 is in R1C3 -didn't work; than tried that 9 is in that field R1C3 and it worked. But i would like to know is there a logical solution?!

5 7 x x x 2 1 x 3
8 1 3 9 5 7 6 2 4
6 x 2 x 1 3 7 x 5
7 6 5 1 2 x 3 4 x
x 3 1 5 x 4 x 7 x
x x x 3 7 x 5 1 x
3 5 x 2 x 1 4 6 7
4 2 7 x 3 x x 5 1
1 x 6 7 4 5 x 3 x

Thanks
blob

Posts: 1
Joined: 01 October 2005

There's a Naked Pair {2,9} in Box 4. This allows you to create another naked pair {4,8} in the same box. This pair allows you to remove some candidate 8's from row 6. (Of course 'Possibles locked in a row' (as angus's says) would have done all that as well, but it all depends on what you see first).
After this, Colouring 9's will show that r5c7 and r9c9 can't be 9's.

Next, a couple of Forcing Chains stemming from r3c2 will fix r1c5 as '6', and then you can fill in all the remaining 6's.

Then *phew*, some more colouring of 8's shows that r4c6 can't be 8. So, you know r5c5 is. From this point the puzzle, as they say, is trivial.

Hope you got all that. I'll be asking questions later.
Karyobin

Posts: 396
Joined: 18 June 2005