I've got a puzzle here where one of the blocks looks like this:
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5 4 {7, 8}
{3, 6, 8} 2 {6, 8}
{3, 7, 8} 1 9
Where {x, y .. } indicates that the cell must contain one of x, y, ...
(I didn't see a standard notation, so I've come up with this in the hope that it's not too confusing).
Let us refer to:
the {7, 8} choice as A
the {3, 6, 8} choice as B
the {6, 8} choice as C
the {3, 7, 8} choice as D
Now, given an analysis of (what I understand of) naked pairs, we get:
- A and D are 7 and 8
- B and C are 6 and 8
- one of B and D MUST be 3.
If the first statement holds true, then the 3 choice can be removed from B. This means that B must hold 3, which means that C holds 6, which leaves A and D. However, the same logic holds for the second statement, with A swapped for C and B swapped for D.
The question I have is - have I missed anything about this situation? Is there anything else I can work out with the information given? It feels like I should...