- Code: Select all
*-------*-------*-------*
| B B * | * . . | * . . | B = Base Cells,(candidates=abcd)
| . . * | T1 . . | X . . | T1/T2 = Target Cells
| . . * | X . . | T2 . . | X= Given Cells, not equal to a/b/c/d
*-------*-------*-------* a/b/c/d= Given Cells
| . . X | X . . | . . . |
| . . . | . a . | . . d |
| . . . | . . b | . c . |
*-------*-------*-------*
| . . X | X . . | X . . | * = 'Escape' Cells
| . . . | . d . | . a . |
| . . . | . . c | . . b |
*-------*-------*-------*
CLb CL1 CL2 CL = Cross-Line
Based On the JE2 Pattern, pattern requirements:
1) 4 candidates in Base Cells (abcd)
2) The given cells a/b/c/d placed in 4 blocks formed a rectangle, e.g. Block 5/6/8/9. Ofcause, a/b/c/d CAN’T be placed in same row or column to any X.
3) abcd divided in two pairs, ab/cd, same pair placed in diagonally block. for example: a and b placed in Block 5 and 9, c and d placed in Block 6 and 8.
4) Compare to JE2 Pattern, one of the given X lost in CL1 OR CL2. (X LOST IN CL2 in this example,r4c7)
5) The Base Cells placed in the only block, which is not in same band or stack of the blocks placed a/b/c/d. for example, if a/b/c/d placed in Block 5/6/8/9, then Base Cells placed in Block 1.
2. conclusion
if X lost in CL2, then T1=abcd (example in this topic)
if X lost in CL1, then T2=abcd
3. extension pattern: AK MODE (another name: adrenaline infusion mode)
the AK MODE is like "adrenaline infusion" to a Weak Exocet, which cause some extension conclusions.
- Code: Select all
*-------*-------*-------*
| B B * | * . . | * . . | B = Base Cells,(candidates=abcd)
| . . * | T1 . . | X . . | T1/T2 = Target Cells
| . . * | X . . | T2 . . | X= Given Cells, not equal to a/b/c/d
*-------*-------*-------* a/b/c/d= Given Cells
| . . X | X . . | . . . |
|Y Y . | . a . | . . d |
|Y Y . | . . b | . c . |
*-------*-------*-------*
|Z Z X | X . . | X . . | * = 'Escape' Cells
| . . . | . d W | . a W|
| . . . | . W c | . W b |
*-------*-------*-------*
CLb CL1 CL2 CL = Cross-Line
1. Y cell placed in "Y block". Y block is the “crossover” block of the BASE block and the X LOST block. in this example, the X LOST block is block 6, the BASE block is block 1, so the Y block is block 4.
2. Y cell CAN'T place in same row/column with X.
if we place 1 a or b ( can't be c and d , givens in the X LOST block) in one of the Y cells, there comes some extension conclusions:
1. T1=abcd AND T2=abcd
2. Z=abcd
3. W<>abcd
by 辉煌背后的衰落 AND 探长(borescoper)
