Just to show, how it can be done manually:
With the information (or suspicion), that there is a digital symmetry we can try to bring it into a normal form:
- Code: Select all
* - - - - - - - - - - - *
| . . . | 4 . . | . 5 . |
| . . 1 | . . 9 | 7 . . |
| 8 . . | . 6 . | . . 2 |
| - - - + - - - + - - - |
| . . 6 | 8 . . | 4 . . |
| . 5 . | . 1 . | . . . |
| 7 . . | . . . | . . 9 |
| - - - + - - - + - - - |
| . 4 . | . 2 . | . . 6 |
| . . . | . . 7 | 1 . . |
| . . 9 | 5 . . | . 8 . |
* - - - - - - - - - - - *
If it is a 2-folded symmetry, the 4 boxes with 2 digits, must either be in b1379 or b2468, the first not possible here.
So switch stacks 12:
- Code: Select all
- - - - * - - - - - - - *
| 4 . . | . . . | . 5 . |
| . . 9 | . . 1 | 7 . . |
| . 6 . | 8 . . | . . 2 |
+ - - - | - - - + - - - |
| 8 . . | . . 6 | 4 . . |
| . 1 . | . 5 . | . . . |
| . . . | 7 . . | . . 9 |
+ - - - | - - - + - - - |
| . 2 . | . 4 . | . . 6 |
| . . 7 | . . . | 1 . . |
| 5 . . | . . 9 | . 8 . |
- - - - * - - - - - - - *
No chance for a central symmetry, so try to bring them to diagonal symmetry (first: main diaginal):
257 maps to 257 (b37), so (b5) 6 maps to itself, 57 to one another and 2 to itself. Then 18 and 49 must be pairs (b24), the missing 3 maps to itself.
The 6 in b159 must be in the main diagonal. Let's move 6 in b5 to the center (all positions in the main diagonal are possible), swap r45c56:
- Code: Select all
- - - - * - - - - - - - *
| 4 . . | . . . | . 5 . |
| . . 9 | . 1 . | 7 . . |
| . 6 . | 8 . . | . . 2 |
+ - - - | - - - + - - - |
| . 1 . | . . 5 | . . . |
| 8 . . | . 6 . | 4 . . |
| . . . | 7 . . | . . 9 |
+ - - - | - - - + - - - |
| . 2 . | . . 4 | . . 6 |
| . . 7 | . . . | 1 . . |
| 5 . . | . 9 . | . 8 . |
- - - - * - - - - - - - *
Now let b5 be fixed and try to adjust the 49's in b68, eg by switching c78 and rotating r789 to 978.
(Simpler is switching r79, but all adjustments will lead to a symmetric puzzle in normal form - if it has the symmetry)
- Code: Select all
- - - - * - - - - - - - *
| 4 . . | . . . | 5 . . |
| . . 9 | . 1 . | . 7 . |
| . 6 . | 8 . . | . . 2 |
+ - - - | - - - + - - - |
| . 1 . | . . 5 | . . . |
| 8 . . | . 6 . | . 4 . |
| . . . | 7 . . | . . 9 |
+ - - - | - - - + - - - |
| . . 7 | . . . | . 1 . |
| 5 . . | . 9 . | 8 . . |
| . 2 . | . . 4 | . . 6 |
- - - - * - - - - - - - *
This also fixes b9 (if it doesn't, it does not have this symmetry).
Now switch r13 to bring 5 in b3 symmetric to 7r7c3, and switch c12 for digits 52 in b7
- Code: Select all
- - - - * - - - - - - - *
| 6 . . | 8 . . | . . 2 |
| . . 9 | . 1 . | . 7 . |
| . 4 . | . . . | 5 . . |
+ - - - | - - - + - - - |
| 1 . . | . . 5 | . . . |
| . 8 . | . 6 . | . 4 . |
| . . . | 7 . . | . . 9 |
+ - - - | - - - + - - - |
| . . 7 | . . . | . 1 . |
| . 5 . | . 9 . | 8 . . |
| 2 . . | . . 4 | . . 6 |
- - - - * - - - - - - - *
Voila, also b124 fit.
Diagonal symmetry, (18)(2)(3)(49)(57)(6)
- Code: Select all
+----------------------+----------------------+----------------------+
| 6 137 135 | 8 45 379 | 1349 39 2 |
| 358 23 9 | 45 1 236 | 346 7 348 |
| 378 4 23-18 | 2369 237 23679 | 5 3689 138 |
+----------------------+----------------------+----------------------+
| 1 79 2346 | 23-49 2348 5 | 2367 2368 378 |
| 79 8 235 | 1239 6 1239 | 1237 4 1357 |
| 345 236 23456 | 7 2348 23-18 | 1236 23568 9 |
+----------------------+----------------------+----------------------+
| 3489 369 7 | 2356 2358 2368 | 23-49 1 345 |
| 34 5 1346 | 1236 9 12367 | 8 23 347 |
| 2 139 138 | 135 3578 4 | 379 359 6 |
+----------------------+----------------------+----------------------+
Remove all but 236 from the main diagonal, stte