How do subset counting and Barn handle this:
Code: Select all
- Code: Select all
.--------------------.--------------.----------------------.
| 234579 2579 234 | 134 8 49 | 14569 5679 124579 |
| 23459 259 1 | 7 349 6 | 8 59 2459 |
| 4789 6 48 | 5 149 2 | 149 3 1479 |
:--------------------+--------------+----------------------:
| 269 4 7 | 26 269 58 | 3 1 58 |
| 1 29 23 | 234 7 58 | 459 589 6 |
| 36 8 5 | 136 136 49 | 7 2 49 |
:--------------------+--------------+----------------------:
| 2578 3 a268 | 9 a26 1 |ab56 4 b578 |
| 457 157 9 | 8 46 3 | 2 b567 17-5 |
| 248 12 2468 | 246 5 7 | 169 689 3 |
'--------------------'--------------'----------------------'
(5=268)r7c357 - (8=675)b9p135 => -5 r8c9
What we have is an overlapping ALS XZ: a=(2568)r7c357, b=(5678)b9p135, x=8, z=5). Subset counting gives: [25678] -> [11211] (+1). Our elimination does not make that sum negative (only zero). How does subset counting work with overlapping ALS moves?
SpAce
Posts: 283
Joined: 22 May 2017
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from my barn code. {and als-xz} {ps my grid system is 0..80 top left to top right and top down order. }
Set a) 2568 @ Cells 56,58,60
Seb b) 5678 @ cells 60,62,70
x = 8, Z = 5,6
61,69,71,78,79,80 <> 5
61 <> 6
or
Set a) 25678 @ cells 56,58,60,62
Set b) 567 @ cells 60,70
x =7, z = 5,6
61,69,71,78,79,80 <> 5
61 <> 6
overlaps are fine as long as they do not contain all the RC of one or both of the overlapping sectors.
for subset counting making the count negative gives direct true eliminations, when a subset with in the cells are "connected" by a subset the zero can force a negative number which is where Almost DDS plays an effect. {as wrote by obiwan} as a person would also checking the subsets counts.
in this case the RC of either 7 or 8 {depending on which of the two is used} contains any of the common digits 5,6 and directly sees a bivalve which shares a "0" sector by placement also reduces the count by 1.
probably something much easier then that to do it... like an counting method that checks that all A&B sectors are eliminated reducing the count twice instead of once...
ps. if you didn't read in one of the linked threads i listed a Sue de coq is the simplest subset counting method as it is a 2 sector disjointed subset.
which is replicated by als-xz double linked rule.
and a death blossom is a 3 sector disjointed subset aka {als-xy rules}
