*8* **2 ***

1*4 57* 2*3

7** *** ***

8*3 1*7 492

*47 *2* 158

2*1 8*4 637

4** 7** **9

5*6 48* **1

*** 2** *4*

Can somebody give me a hand?

*edit : added the 5

13 posts
• Page **1** of **1**

*8* **2 ***

1*4 57* 2*3

7** *** ***

8*3 1*7 492

*47 *2* 158

2*1 8*4 637

4** 7** **9

5*6 48* **1

*** 2** *4*

Can somebody give me a hand?

*edit : added the 5

1*4 57* 2*3

7** *** ***

8*3 1*7 492

*47 *2* 158

2*1 8*4 637

4** 7** **9

5*6 48* **1

*** 2** *4*

Can somebody give me a hand?

*edit : added the 5

Last edited by doku on Sat Sep 10, 2005 6:40 am, edited 1 time in total.

- doku
**Posts:**5**Joined:**10 September 2005

doku wrote:Thanks, but what is meant by a "triple" ?

doku -

Check the candidates in column 2 for rows 2, 4 & 6...

3 numbers, spread across 3 cells - therefore those numbers cannot be candidates in rows 7, 8 & 9 (still looking at column 2 here).

This forces a number into the bottom row of the bottom left block, which enables you to place that number in the bottom middle block.

- whohe
**Posts:**32**Joined:**28 May 2005

It is probably worth going to one of the excelent sites for descriptions of some of the techniques such as triples.

http://www.simes.clara.co.uk/programs/sudokutechniques.htm

http://www.angusj.com/sudoku/

These are both well worth a visit.

http://www.simes.clara.co.uk/programs/sudokutechniques.htm

http://www.angusj.com/sudoku/

These are both well worth a visit.

- SteveF
**Posts:**86**Joined:**26 March 2005

whohe wrote:Check the candidates in column 2 for rows 2, 4 & 6...

3 numbers, spread across 3 cells - therefore those numbers cannot be candidates in rows 7, 8 & 9 (still looking at column 2 here).

This forces a number into the bottom row of the bottom left block, which enables you to place that number in the bottom middle block.

I still don't see it, can you explain it further?

- doku
**Posts:**5**Joined:**10 September 2005

In column 2:

r2c2 can be 6 or 9

r4c2 can be 5 or 6

r6c2 can be 5 or 9

Thus the only three valid candidates for these 3 cells are 5, 6 and 9. Thus the candidates 5, 6 and 9 must go in these three cells and nowhere else. Thesrefore you can eliminate these as candidates from all other cells in column 2.

Having done these eliminations, what is the only value that can go in r8c6?

r2c2 can be 6 or 9

r4c2 can be 5 or 6

r6c2 can be 5 or 9

Thus the only three valid candidates for these 3 cells are 5, 6 and 9. Thus the candidates 5, 6 and 9 must go in these three cells and nowhere else. Thesrefore you can eliminate these as candidates from all other cells in column 2.

Having done these eliminations, what is the only value that can go in r8c6?

- SteveF
**Posts:**86**Joined:**26 March 2005

Hi,

Here is the answer, I use a Excel to support to solve.

685932714

194578263

732641985

863157492

947326158

251894637

418763529

526489371

379215846[/img]

Here is the answer, I use a Excel to support to solve.

685932714

194578263

732641985

863157492

947326158

251894637

418763529

526489371

379215846[/img]

- SkyWu
**Posts:**1**Joined:**10 September 2005

SteveF wrote:In column 2:

r2c2 can be 6 or 9

r4c2 can be 5 or 6

r6c2 can be 5 or 9

Thus the only three valid candidates for these 3 cells are 5, 6 and 9. Thus the candidates 5, 6 and 9 must go in these three cells and nowhere else. Thesrefore you can eliminate these as candidates from all other cells in column 2.

Having done these eliminations, what is the only value that can go in r8c6?

Thanks for the explanation. Somehow i was distracted by the possibility that the 6 or 9 also could go anywhere else in this column. But it isn't. I prefer this method to find the answer rather than the whole solution. Because with the SteveF method i can learn the techniques step by step.

By the way, that hint was the one that solved me the puzzle!

- doku
**Posts:**5**Joined:**10 September 2005

13 posts
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