My first solution was phil's
MUG(456)r19c456 using single external => +4 r9c1; ste
So, my two steps':
- Code: Select all
+-----------------------+-----------------------+----------------------+
| 1 2 3 | 456 56 456 | 7 8 9 |
| 49 45 8 | 3 129 7 | 6 245 124 |
| 479 4567 467 | 19 8 129 | 2345 2345 124 |
+-----------------------+-----------------------+----------------------+
| 2347 1467 5 | 1679 1369 169 | 8 249 247 |
| 347 9 467 | 2 356 8 | 45 1 47 |
| 8 17 27 | 1579 4 159 | 235 2359 6 |
+-----------------------+-----------------------+----------------------+
| 6 47 2479 | 8 129 3 | 124 24 5 |
| 5 8 249 | 149 7 1249 | 124 6 3 |
| 24 3 1 | 456 256 2456 | 9 7 8 |
+-----------------------+-----------------------+----------------------+
1. (5=
62)r19c5 - r9c1 = r4c1 - (2=
1795)r6c2346 => -5 r5c5; lcls, 1 placements
- Code: Select all
+-----------------------+-----------------------+---------------------+
| 1 2 3 | 456 56 456 | 7 8 9 |
| 49 45 8 | 3 129 7 | 6 245 124 |
| 479 4567 467 | 19 8 129 | 234 2345 124 |
+-----------------------+-----------------------+---------------------+
| 2347 1467 5 | 1679 1369 169 | 8 249 247 |
| 347 9 467 | 2 36 8 | 5 1 47 |
| 8 17 27 | 1579 4 159 | 23 239 6 |
+-----------------------+-----------------------+---------------------+
| 6 47 2479 | 8 129 3 | 124 24 5 |
| 5 8 249 | 149 7 1249 | 124 6 3 |
| 24 3 1 | 456 256 2456 | 9 7 8 |
+-----------------------+-----------------------+---------------------+
2. (6)r5c5 = r5c3 - r3c3 = (6
5-3)r3c28 = r6c8 - (3=2)r6c7 - r6c3 = (23)r45c1 => -3 r5c5; ste