Vanhegan fiendish January 30, 2012

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Vanhegan fiendish January 30, 2012

Postby ArkieTech » Thu Jan 31, 2013 6:13 am

Code: Select all
 *-----------*
 |.9.|4..|75.|
 |..7|..6|2.9|
 |2.5|..8|.4.|
 |---+---+---|
 |...|.9.|..7|
 |.5.|...|.2.|
 |3..|.4.|...|
 |---+---+---|
 |.6.|8..|4.5|
 |9.3|5..|1..|
 |.48|..7|.9.|
 *-----------*


Play/Print this puzzle online
dan
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Re: Vanhegan fiendish January 30, 2012

Postby Leren » Thu Jan 31, 2013 6:24 am

Code: Select all
*--------------------------------------------------------------------------------*
| 68      9       16       | 4      e12      123      | 7       5      b38-1     |
| 4       138     7        | 3-1     5       6        | 2      a18      9        |
| 2       13      5        | 9       7       8        | 36      4       136      |
|--------------------------+--------------------------+--------------------------|
| 68      128     4        | 126     9       125      | 58      3       7        |
| 7       5       16       | 136     8       13       | 9       2       4        |
| 3       28      9        | 7       4       25       | 58      16      16       |
|--------------------------+--------------------------+--------------------------|
| 1       6       2        | 8       3       9        | 4       7       5        |
| 9       7       3        | 5      d26      4        | 1       68     c268      |
| 5       4       8        | 12      126     7        | 36      9       236      |
*--------------------------------------------------------------------------------*


(1=8) r2c8 - r1c9 = (8-2) r8c9 = r8c5 - (2=1) r1c5 => r1c9, r2c4 <> 1; stte

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Re: Vanhegan fiendish January 30, 2012

Postby daj95376 » Thu Jan 31, 2013 8:42 am

I didn't try to find Mike Barker's UR classification for this pattern.

Code: Select all
 +-----------------------------------------------------+
 |  68   9    16   |  4    12   123  |  7    5   @138  |
 |  4    138  7    |  13   5    6    |  2   @18   9    |
 |  2    13   5    |  9    7    8    | *36   4   *36+1 |
 |-----------------+-----------------+-----------------|
 |  68   128  4    |  126  9    125  |  58   3    7    |
 |  7    5    16   |  136  8    13   |  9    2    4    |
 |  3    28   9    |  7    4    25   |  58   16  #16   |
 |-----------------+-----------------+-----------------|
 |  1    6    2    |  8    3    9    |  4    7    5    |
 |  9    7    3    |  5    26   4    |  1    68   268  |
 |  5    4    8    |  12   126  7    | *36   9   *36+2 |
 +-----------------------------------------------------+
 # 42 eliminations remain

 possible r39c79 UR for <36>:

 (2)r9c9 =UR= (1)r3c9 - (1=83)r2c8,r1c9 - (3)r9c9 \
                      - (1=6 )r6c9      - (6)r9c9  =  (2)r9c9
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Re: Vanhegan fiendish January 30, 2012

Postby Leren » Thu Jan 31, 2013 9:05 am

Code: Select all
*--------------------------------------------------------------------------------*
| 68      9       16       | 4       12      12-3     | 7       5       138      |
| 4      e138     7        |f13      5       6        | 2       18      9        |
| 2      d13      5        | 9       7       8        | 36      4       136      |
|--------------------------+--------------------------+--------------------------|
| 68     c128     4        |b126     9      b125      | 58      3       7        |
| 7       5       16       | 16-3    8      a13       | 9       2       4        |
| 3       28      9        | 7       4       25       | 58      16      16       |
|--------------------------+--------------------------+--------------------------|
| 1       6       2        | 8       3       9        | 4       7       5        |
| 9       7       3        | 5       26      4        | 1       68      268      |
| 5       4       8        | 12      126     7        | 36      9       236      |
*--------------------------------------------------------------------------------*


w-wing with pincer transport: (3=1) r5c6 - r4c46 = r4c2 - (1=3) r3c2 - r2c2 = r2c4 => r1c6, r5c4 <> 3; stte

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Re: Vanhegan fiendish January 30, 2012

Postby eleven » Thu Jan 31, 2013 9:39 am

daj95376 wrote:I didn't try to find Mike Barker's UR classification for this pattern.

At least you can write it as ALS chain with the external candidates 3r1c9=6(r8c89):
[edit: corrected, thanks to Danny]
(2=136)r369c9-3r1c9=[UR]=6(r8c89)-(6=23)r9c79 => r9c9=2

Code: Select all
 +-----------------------------------------------------+
 |  68   9    16   |  4   b12  *123  |  7    5    138  |
 |  4   *1-38 7    | c13   5    6    |  2    18   9    |
 |  2   a13   5    |  9    7    8    |  36   4    136  |
 |-----------------+-----------------+-----------------|
 |  68  #128  4    |  126  9   #125  | #58   3    7    |
 |  7    5    16   |  136  8    13   |  9    2    4    |
 |  3   #28   9    |  7    4   #25   | #58   16   16   |
 |-----------------+-----------------+-----------------|
 |  1    6    2    |  8    3    9    |  4    7    5    |
 |  9    7    3    |  5    26   4    |  1    68   268  |
 |  5    4    8    |  12   126  7    |  36   9    236  |
 +-----------------------------------------------------+

DP 258 in r46c267, external candidates 8r2c2=2r1c6
r2c2=8->r3c2=3
r1c6=2->r1c5=1->r2c4=3
3r3c2=(3-8)r2c2=[DP]=2r1c6-(2=13)r1c5,r2c4 => r2c2<>3
Last edited by eleven on Thu Jan 31, 2013 8:36 pm, edited 1 time in total.
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Re: Vanhegan fiendish January 30, 2012

Postby pjb » Thu Jan 31, 2013 11:50 am

Using the UR at r3c79 & r9c79 in a chain:

(2=6)r8c5 - (6=8)r8c8 - (8=1)r2c8 - (1=2)UR r3c79;r9c79: => r8c9, r9c45 <> 2; stte

Phil
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Re: Vanhegan fiendish January 30, 2012

Postby tlanglet » Thu Jan 31, 2013 2:12 pm

I looked for something a bit different than my normal routine........

AXY-wing(18-3)r2c84,r1c9 with (38=1)r1c9
[xy-wing(18-3)r2c84,r1c9 => r1c6<>3] = [1r1c9-(1=8)r1c31-(8=6)r4c1-(6=12)r49c4-(1=3)r2c4 => r1c6<>3] =>r1c6<>3
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Re: Vanhegan fiendish January 30, 2012

Postby daj95376 » Thu Jan 31, 2013 5:34 pm

eleven wrote:
daj95376 wrote:I didn't try to find Mike Barker's UR classification for this pattern.

At least you can write it as ALS chain with the external candidates 3r1c9=6(r8c89):
(2=136)r396c9-3r1c9=[UR]=6(r8c89)-(6=23)r9c79 => r9c9=2

Code: Select all
 +-----------------------------------------------------+
 |  68   9    16   |  4   b12  *123  |  7    5    138  |
 |  4   *1-38 7    | c13   5    6    |  2    18   9    |
 |  2   a13   5    |  9    7    8    |  36   4    136  |
 |-----------------+-----------------+-----------------|
 |  68  #128  4    |  126  9   #125  | #58   3    7    |
 |  7    5    16   |  136  8    13   |  9    2    4    |
 |  3   #28   9    |  7    4   #25   | #58   16   16   |
 |-----------------+-----------------+-----------------|
 |  1    6    2    |  8    3    9    |  4    7    5    |
 |  9    7    3    |  5    26   4    |  1    68   268  |
 |  5    4    8    |  12   126  7    |  36   9    236  |
 +-----------------------------------------------------+

DP 258 in r46c267, external candidates 8r2c2=2r1c6
r2c2=8->r3c2=3
r1c6=2->r1c5=1->r2c4=3

3r3c2=(3-8)r2c2=[DP]=2r1c6-(2=13)r1c5,r2c4 => r2c2<>3

I was more interested in using a network to show r3c9=1 => r9c9<>36=2. I used the UR to create a discontinuous loop containing the network. I thought it was a reasonable solution.

Incidentally, this also works for your chain.

Code: Select all
(8)r2c2 =DP= (2)r1c6 - (2=1)r1c5 - (1=3)r2c4  =>  r2c3<>3
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Re: Vanhegan fiendish January 30, 2012

Postby Marty R. » Thu Jan 31, 2013 5:41 pm

Code: Select all
+-----------+-------------+-----------+
| 68 9   16 | 4   12  123 | 7  5  138 |
| 4  138 7  | 13  5   6   | 2  18 9   |
| 2  13  5  | 9   7   8   | 36 4  136 |
+-----------+-------------+-----------+
| 68 128 4  | 126 9   125 | 58 3  7   |
| 7  5   16 | 136 8   13  | 9  2  4   |
| 3  28  9  | 7   4   25  | 58 16 16  |
+-----------+-------------+-----------+
| 1  6   2  | 8   3   9   | 4  7  5   |
| 9  7   3  | 5   26  4   | 1  68 268 |
| 5  4   8  | 12  126 7   | 36 9  236 |
+-----------+-------------+-----------+

Play this puzzle online at the Daily Sudoku site

UR36r39c79 (2r9c9=1r3c9)-(1=8)r2c8-(8=6)r8c8-(6=2)r8c5=>r8c9<>2
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Re: Vanhegan fiendish January 30, 2012

Postby eleven » Thu Jan 31, 2013 8:56 pm

daj95376 wrote:I was more interested in using a network to show r3c9=1 => r9c9<>36=2. I used the UR to create a discontinuous loop containing the network. I thought it was a reasonable solution

Thanks for correcting my chain.

No question, that it was a reasonable solution (as well as Marty's recently, as JC Van Hay had pointed out - and SudoQ's solutions have the allure, that it is not immediately obvious, what he did).
But sorry, i could not resist to apply this aesthetical ALS-AIC writing.
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