Vanhegan Fiendish December 19, 2012

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Vanhegan Fiendish December 19, 2012

Postby ArkieTech » Fri Dec 21, 2012 8:14 am

Code: Select all
 *-----------*
 |4..|...|..9|
 |.76|.2.|18.|
 |91.|.8.|.57|
 |---+---+---|
 |...|192|...|
 |.9.|...|.4.|
 |...|745|...|
 |---+---+---|
 |52.|.1.|.76|
 |.34|.6.|52.|
 |8..|...|..3|
 *-----------*
 


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Re: Vanhegan Fiendish December 19, 2012

Postby storm_norm22 » Fri Dec 21, 2012 11:05 am

Code: Select all
.---------------.---------------.---------------.
| 4    5    8   | 36   7    1   | 2    36   9   |
| 3    7    6   | 5    2    9   | 1    8    4   |
| 9    1    2   | 346  8    346 | 36   5    7   |
:---------------+---------------+---------------:
| 67   4    357 | 1    9    2   | 368  36   58  |
| 12   9    15  | 68   3    68  | 7    4    125 |
| 126  8    13  | 7    4    5   | 369  19   12  |
:---------------+---------------+---------------:
| 5    2    9   | 348  1    348 | 48   7    6   |
| 17   3    4   | 9    6    78  | 5    2    18  |
| 8    6    17  | 2    5    47  | 49   19   3   |
'---------------'---------------'---------------'

(8=369)r46c78 - (9=1)r6c8 - (1)r9c8 = (1)r9c3 - (1=5)r5c3 - (5)r5c9 = (5)r4c9; r4c9 <> 8
Last edited by storm_norm22 on Fri Dec 21, 2012 12:54 pm, edited 1 time in total.
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Re: Vanhegan Fiendish December 19, 2012

Postby ArkieTech » Fri Dec 21, 2012 12:23 pm

Code: Select all
 *--------------------------------------------------*
 | 4    5    8    | 36   7    1    | 2    36   9    |
 | 3    7    6    | 5    2    9    | 1    8    4    |
 | 9    1    2    | 346  8    346  | 36   5    7    |
 |----------------+----------------+----------------|
 | 67   4    357  | 1    9    2    | 368  36   58   |
 | 12   9   a15   | 68   3    68   | 7    4   b125  |
 | 126  8    13   | 7    4    5    | 369 b19  b12   |
 |----------------+----------------+----------------|
 | 5    2    9    | 348  1    348  | 48   7    6    |
 | 17   3    4    | 9    6    78   | 5    2    18   |
 | 8    6    7-1  | 2    5    47   | 49  c19   3    |
 *--------------------------------------------------*
als xy-wing
(1=5)r5c3-(5=9)r56c9,r6c8-(9=1)r9c8 => -1r9c3; stte
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Re: Vanhegan Fiendish December 19, 2012

Postby tlanglet » Fri Dec 21, 2012 12:48 pm

Type 6 UR(12)r56c19[6r6c1=5r5c9]-(5=8=1)r48c9-r9c8=r9c3-(1=5)r5c3 Conflict => r5c9<>5;
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Re: Vanhegan Fiendish December 19, 2012

Postby tlanglet » Fri Dec 21, 2012 1:06 pm

Another fun solution is an Almost Sue de Coq:

[SdC(12369)r6c789, (12)r6c1, (36)r4c8 => r4c7<>36] = [6r6c1-(6=7=1)r48c1-(1=8)r8c9-r4c9=8r4c7 => r4c7<>36] => r4c7<>36
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Re: Vanhegan Fiendish December 19, 2012

Postby SudoQ » Fri Dec 21, 2012 3:03 pm

.. or like this:
Code: Select all
|-------------|-------------|--------------|
| 4    5  8   | 36   7  1   | 2    36  9   |
| 3    7  6   | 5    2  9   | 1    8   4   |
| 9    1  2   | 346  8  346 | 36   5   7   |
|-------------|-------------|--------------|
| 6(7) 4 3(57)| 1    9  2   | 368  36 (5)-8|
| 12   9  15  | 68   3  68  | 7    4   125 |
| 126  8  13  | 7    4  5   | 369  19  12  |
|-------------|-------------|--------------|
| 5    2  9   | 348  1  348 | 48   7   6   |
|(17)  3  4   | 9    6  78  | 5    2  (18) |
| 8    6  17  | 2    5  47  | 49   19  3   |
|-------------|-------------|--------------|
/SudoQ
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Re: Vanhegan Fiendish December 19, 2012

Postby tlanglet » Fri Dec 21, 2012 3:54 pm

SudoQ wrote:.. or like this:
Code: Select all
|-------------|-------------|--------------|
| 4    5  8   | 36   7  1   | 2    36  9   |
| 3    7  6   | 5    2  9   | 1    8   4   |
| 9    1  2   | 346  8  346 | 36   5   7   |
|-------------|-------------|--------------|
| 6(7) 4 3(57)| 1    9  2   | 368  36 (5)-8|
| 12   9  15  | 68   3  68  | 7    4   125 |
| 126  8  13  | 7    4  5   | 369  19  12  |
|-------------|-------------|--------------|
| 5    2  9   | 348  1  348 | 48   7   6   |
|(17)  3  4   | 9    6  78  | 5    2  (18) |
| 8    6  17  | 2    5  47  | 49   19  3   |
|-------------|-------------|--------------|
/SudoQ

SudoQ, I am unable interpret you post. Please notate your logic.

Ted
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Re: Vanhegan Fiendish December 19, 2012

Postby SudoQ » Fri Dec 21, 2012 4:13 pm

tlanglet wrote:SudoQ, I am unable interpret you post. Please notate your logic.

A chain of bi-cells:
Code: Select all
r8c9 = 1/8
r8c1 = 1/7
r4/8c1 = 7
r4c1/3 = 7
r4c3/9 = 5

=> r4c9 =5/<>8
/SudoQ
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Re: Vanhegan Fiendish December 19, 2012

Postby Marty R. » Fri Dec 21, 2012 6:55 pm

Code: Select all
+-----------+-----------+------------+
| 4   5 8   | 36  7 1   | 2   36 9   |
| 3   7 6   | 5   2 9   | 1   8  4   |
| 9   1 2   | 346 8 346 | 36  5  7   |
+-----------+-----------+------------+
| 67  4 357 | 1   9 2   | 368 36 58  |
| 12  9 15  | 68  3 68  | 7   4  125 |
| 126 8 13  | 7   4 5   | 369 19 12  |
+-----------+-----------+------------+
| 5   2 9   | 348 1 348 | 48  7  6   |
| 17  3 4   | 9   6 78  | 5   2  18  |
| 8   6 17  | 2   5 47  | 49  19 3   |
+-----------+-----------+------------+

Play this puzzle online at the Daily Sudoku site

I also used the UR.

Type 6 UR (12)r5c19r6c19 (6r6c1=5r5c9)-(1235=6)r5c13r6c31=>r6c1=6

-or-

Type 6 UR (12)r5c19r6c19 (6r6c1=5r5c9)-(58=36)r4c978-6r4c1=r6c1=>r6c1=6

Have no idea as to validity of either notation.
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Re: Vanhegan Fiendish December 19, 2012

Postby daj95376 » Fri Dec 21, 2012 8:19 pm

Marty R. wrote:
Code: Select all
+-----------+-----------+------------+
| 4   5 8   | 36  7 1   | 2   36 9   |
| 3   7 6   | 5   2 9   | 1   8  4   |
| 9   1 2   | 346 8 346 | 36  5  7   |
+-----------+-----------+------------+
| 67  4 357 | 1   9 2   | 368 36 58  |
| 12  9 15  | 68  3 68  | 7   4  125 |
| 126 8 13  | 7   4 5   | 369 19 12  |
+-----------+-----------+------------+
| 5   2 9   | 348 1 348 | 48  7  6   |
| 17  3 4   | 9   6 78  | 5   2  18  |
| 8   6 17  | 2   5 47  | 49  19 3   |
+-----------+-----------+------------+


Type 6 UR (12)r5c19r6c19 (6r6c1=5r5c9)-(1235=6)r5c13r6c31=>r6c1=6

-or-

Type 6 UR (12)r5c19r6c19 (6r6c1=5r5c9)-(58=36)r4c978-6r4c1=r6c1=>r6c1=6

Have no idea as to validity of either notation.

Marty, I only checked your first solution, but I was able to follow it okay. You did use one more cell than necessary:

(12) UR r56c19 (6r6c1 = 5r5c9) - (5=6)ans:r5c31,r6c1 => r6c1=6




I've noticed a lot of XrMcN notation -- instead of (X)rMcN -- lately. I assume that (almost) everyone has switched to this usage???
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