Vanhegan fiendish December 10, 2012

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Vanhegan fiendish December 10, 2012

Postby ArkieTech » Mon Dec 10, 2012 6:58 am

Code: Select all
 *-----------*
 |...|163|7.8|
 |..8|..5|.91|
 |...|.2.|3..|
 |---+---+---|
 |9..|5..|.7.|
 |.8.|3.2|.5.|
 |.2.|..4|..9|
 |---+---+---|
 |..9|.8.|...|
 |81.|2..|9..|
 |4.2|931|...|
 *-----------*


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Re: Vanhegan fiendish December 10, 2012

Postby Leren » Mon Dec 10, 2012 8:46 am

Code: Select all
*--------------------------------------------------------------------------------*
| 25      9       45       | 1       6       3        | 7       24      8        |
| 236     36      8        | 7       4       5        | 26      9       1        |
| 167     467     1467     | 8       2       9        | 3       46      5        |
|--------------------------+--------------------------+--------------------------|
| 9       346     346      | 5       1       8        | 24      7      b23       |
| 17      8       147      | 3       9       2        | 14      5       6        |
| 135     2       135      | 6       7       4        | 18     c138     9        |
|--------------------------+--------------------------+--------------------------|
| 367     3567    9        | 4       8       67       | 1256   d136-2  a23       |
| 8       1       367      | 2       5       67       | 9       36      4        |
| 4       56      2        | 9       3       1        | 568     68      7        |
*--------------------------------------------------------------------------------*


H Wing: (2=3) r7c9 - r4c9 = (3-1) r6c8 = r7c8 => r7c8 <2>

Leren
Last edited by Leren on Mon Dec 10, 2012 8:19 pm, edited 1 time in total.
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Re: Vanhegan fiendish December 10, 2012

Postby David P Bird » Mon Dec 10, 2012 12:08 pm

Leren (and others), the practice of keeping the candidate list in a cell in ascending order and inserting a '-' sign in front of each eliminated candidate would take up unnecessary space when there is more than one elimination in a cell. The customary method has been to move any eliminated candidates to the end of the list preceded by a single '-' sign.

I know I'm a pain on such matters, but when readers have to adjust to different representations of the same thing, at best it slows them down, and at worst it leads to misunderstandings when they jump the wrong way.
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Re: Vanhegan fiendish December 10, 2012

Postby ArkieTech » Mon Dec 10, 2012 1:17 pm

another way to same result

Code: Select all
 *-----------------------------------------------------------*
 | 25    9     45    | 1     6     3     | 7    a24    8     |
 | 236   36    8     | 7     4     5     | 26    9     1     |
 | 167   467   1467  | 8     2     9     | 3    b46    5     |
 |-------------------+-------------------+-------------------|
 | 9     346   346   | 5     1     8     | 24    7     23    |
 | 17    8     147   | 3     9     2     | 14    5     6     |
 | 135   2     135   | 6     7     4     | 18    138   9     |
 |-------------------+-------------------+-------------------|
 | 367   3567  9     | 4     8     67    | 1256  136-2 d23   |
 | 8     1     367   | 2     5     67    | 9    c36    4     |
 | 4     56    2     | 9     3     1     | 568   68    7     |
 *-----------------------------------------------------------*
xy-chain
(2=4)r1c8-(4=6)r3c8-(6=3)r8c8-(3-2)r7c9 => -2r7c8; stte
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Re: Vanhegan fiendish December 10, 2012

Postby tlanglet » Mon Dec 10, 2012 1:52 pm

Still another view of the same general logic......

2r4c7=2r4c9-(2=3)r7c9-(3=6)r8c8-(6=4=2)r31c8 => r2c7<>2

and

ANP(17=4)r5c13-r1c3=(4=6=3)r138c8-(3=18)r6c87 => r5c7<>1
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Re: Vanhegan fiendish December 10, 2012

Postby Marty R. » Mon Dec 10, 2012 10:15 pm

Code: Select all
+---------------+--------+--------------+
| 25  9    45   | 1 6 3  | 7    24   8  |
| 236 36   8    | 7 4 5  | 26   9    1  |
| 167 467  1467 | 8 2 9  | 3    46   5  |
+---------------+--------+--------------+
| 9   346  346  | 5 1 8  | 24   7    23 |
| 17  8    147  | 3 9 2  | 14   5    6  |
| 135 2    135  | 6 7 4  | 18   138  9  |
+---------------+--------+--------------+
| 367 3567 9    | 4 8 67 | 1256 1236 23 |
| 8   1    367  | 2 5 67 | 9    36   4  |
| 4   56   2    | 9 3 1  | 568  68   7  |
+---------------+--------+--------------+

Play this puzzle online at the Daily Sudoku site

More complicated than the above solutions. Start with a Kite on 4 emanating from box 1, then extend it in stack 3.

Hope the notation's OK, at least one of them, lest I incur Ted's wrath. :lol:

4r4c1=r3c2-r1c3=r1c8-(4=6)r3c8-(2368=1)r7896c8-(1=4)r5c7=>r4c7<>4

-or-

4r4c2=r3c2=r1c3-(4=2)-(2r7c8=1r6c8)-(1=4)r5c7=>r4c7<>4
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