The New Sudoku Players' Forum

[ArkieTech]

Code: Select all

 *-----------*
 |6.2|..3|...|
 |.93|...|4..|
 |1.4|76.|...|
 |---+---+---|
 |.6.|.7.|..4|
 |.31|.2.|98.|
 |4..|.3.|.5.|
 |---+---+---|
 |...|.17|6.3|
 |..7|...|54.|
 |...|3..|2.8|
 *-----------*


Play/Print this puzzle online

[storm_norm22]

almost ER !

the way I visualized this was I imagined that there was in fact an ER on 8's. like this

(8)r8c5 = (8)r2c5 - (8)r2c1 = (8)r13c2

which eliminates the 8 in r8c2. this of course is only fantasy since we know that there are three 8's in column 5.
now that I had a visual on the ER... if that ER is false, then the 8 in r1c5 is true... leads to

(8)r1c5 - (8=7)r1c7 - (7)r1c2 = (58)r13c2

this tells us that the ER on 8's and the pair (58)r13c2 are strongly inferenced. in other words, neither the "imagined" ER nor the "imagined" 58 pair can both be false.
we see they both eliminate the 8 in r8c2. bye bye 8. bye bye puzzle.



this is the chain

Code: Select all

Kraken column 5 on candidate 8; r8c2 <>8

(8)r8c5
||
(8)r2c5 - (8)r2c1 = (8)r13c2
||
(8)r1c5 - (8=7)r1c7 - (7)r1c2 = (58)r13c2

[ArkieTech]

almost ER !

WOW!

Code: Select all

 *-----------------------------------------------------------*
 | 6     578   2     | 4589  4589  3     | 78    1     579   |
 | 78    9     3     | 1258  58    1258  | 4     6     257   |
 | 1     58    4     | 7     6     2589  | 38    23    259   |
 |-------------------+-------------------+-------------------|
 | 258   6     589   | 1589  7     1589  | 13    23    4     |
 |a57    3     1     | 456   2     456   | 9     8    b67    |
 | 4    d28-7  89    | 1689  3     1689  | 17    5    c267   |
 |-------------------+-------------------+-------------------|
 | 258   4     58    | 28    1     7     | 6     9     3     |
 | 3     28    7     | 2689  89    2689  | 5     4     1     |
 | 9     1     6     | 3     45    45    | 2     7     8     |
 *-----------------------------------------------------------*
L-wing
7r5c1=(7-6)r5c9=(6-2)r6c9=2r6c2 => -7r6c2; stte

[tlanglet]

Got a late start today......

ANP(58=7*)r31c2-(7=8)r1c7-(8=3=2)r3c78-r4c8=r4c1-(27*=8)r6c2

Ted

[tlanglet]

almost ER !

the way I visualized this was I imagined that there was in fact an ER on 8's. like this

(8)r8c5 = (8)r2c5 - (8)r2c1 = (8)r13c2

which eliminates the 8 in r8c2. this of course is only fantasy since we know that there are three 8's in column 5.
now that I had a visual on the ER... if that ER is false, then the 8 in r1c5 is true... leads to

(8)r1c5 - (8=7)r1c7 - (7)r1c2 = (58)r13c2

this tells us that the ER on 8's and the pair (58)r13c2 are strongly inferenced. in other words, neither the "imagined" ER nor the "imagined" 58 pair can both be false.
we see they both eliminate the 8 in r8c2. bye bye 8. bye bye puzzle.



this is the chain

Code: Select all

Kraken column 5 on candidate 8; r8c2 <>8

(8)r8c5
||
(8)r2c5 - (8)r2c1 = (8)r13c2
||
(8)r1c5 - (8=7)r1c7 - (7)r1c2 = (58)r13c2

Norm,

I am a fan of "almost" patterns and have found that they seem to be very effective (that is, very destructive).
The result of my first attempt on this puzzle using an ANP() is posted.

Ted

[Marty R.]

Code: Select all

+-------------+----------------+-----------+
| 6   578 2   | 4589 4589 3    | 78 1  579 |
| 78  9   3   | 1258 58   1258 | 4  6  257 |
| 1   58  4   | 7    6    2589 | 38 23 259 |
+-------------+----------------+-----------+
| 258 6   589 | 1589 7    1589 | 13 23 4   |
| 57  3   1   | 456  2    456  | 9  8  67  |
| 4   278 89  | 1689 3    1689 | 17 5  267 |
+-------------+----------------+-----------+
| 258 4   58  | 28   1    7    | 6  9  3   |
| 3   28  7   | 2689 89   2689 | 5  4  1   |
| 9   1   6   | 3    45   45   | 2  7  8   |
+-------------+----------------+-----------+


Play this puzzle online at the Daily Sudoku site

A too-long chain.

(2=8)r8c2-(852=7)r361c2-(7=8)r1c7-(8=3)r3c7-(3=1)r4c7-(1=7)r6c7-(736=2)r4c8,r56c9=>r6c2<>2

[DonM]

Code: Select all

+-------------+----------------+-----------+
| 6   578 2   | 4589 4589 3    | 78 1  579 |
| 78  9   3   | 1258 58   1258 | 4  6  257 |
| 1   58  4   | 7    6    2589 | 38 23 259 |
+-------------+----------------+-----------+
| 258 6   589 | 1589 7    1589 | 13 23 4   |
| 57  3   1   | 456  2    456  | 9  8  67  |
| 4   278 89  | 1689 3    1689 | 17 5  267 |
+-------------+----------------+-----------+
| 258 4   58  | 28   1    7    | 6  9  3   |
| 3   28  7   | 2689 89   2689 | 5  4  1   |
| 9   1   6   | 3    45   45   | 2  7  8   |
+-------------+----------------+-----------+


This should also do the trick:
(7)r5c1=(7-2)r6c2=r4c1-r4c8=r3c8-als(2=579)r123c9 => r5c9<>7=6 stte

Edit: Corrected 3, count'em, 3 notation errors in one little chain- that's what happens when constructing a chain is the last thing you do at night! (At least the logic was correct )