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by **Arnie** » Tue May 24, 2005 9:40 am

I cannot see any xwings or other clues to progress this puzzle. Any suggestions appreciated

*** *72 31*
*** 96* **5
**8 *43 *9*

1** *** *2*
7** *** **9
*5* *** **3

*** 316 9**
3** 784 ***
864 259 731

by **su_doku** » Tue May 24, 2005 9:52 am

Look at box 1 you'll see only 1 number can go into r1c2

by **Arnie** » Tue May 24, 2005 9:56 am

....r1c2 can have 4 or 9...

by **su_doku** » Tue May 24, 2005 10:04 am

yes Arnie ignore previous post - mixed my pencil marks

by **su_doku** » Tue May 24, 2005 10:16 am

Arnie check box 7 - the pairs in r8c2, r8c3 and r7c2, r7c3 should allow you to fill in r7c1

by **Animator** » Tue May 24, 2005 10:18 am

Take a close look at row 2...

And su_doku, are you sure about box 7? (as in, I can't see an immediate reason why it would be possible to fill in r7c1)

by **Animator** » Tue May 24, 2005 10:21 am

Ignore what I said about row 2... it's incorrect aswell...

by **su_doku** » Tue May 24, 2005 10:27 am

as sure as I can be...

I see pair 1,9 in r8c2, r8c3 - that leaves 2,5 and 7 for the remaining 3 cells in box7.

But the two of column 1 is in box 1 (r2c1 or r3c1) - hence the pair of 2 and 7 in r7c2 and r7c3

by **Animator** » Tue May 24, 2005 10:30 am

It is correct, but you left an important hint out: first look at box 1, and pay extra attention to the numbers 1, 3 and 7.

(Spotting the pairs on row 8 and row 9 where easy, I wasn't seeing the one in box 1, which is why I was unsure if your hint was correct)

by **Arnie** » Tue May 24, 2005 10:34 am

Thanks - i now see the "triplet" of 1,3 and 7 in r2c2,3 and r3c2.

by **simes** » Tue May 24, 2005 11:01 am

Are you folks sure about this?

AFAIK:
R2C2 has candidates 1,2,3,4,7
R2C3 has candidates 1,2,3,7
R3C2 has candidates 1,2,7

There can only be a triplet if you have somehow eliminated the 2s and 4s? (or 3s and 4s)

by **simes** » Tue May 24, 2005 11:25 am

Well OK, but a subset of 5 numbers? Did you spot this manually or have a little electronic help?

by **Animator** » Tue May 24, 2005 11:37 am

Take a different look at it... where can the numbers 1, 3 and 7 go? there are only three cells that can have one of those...

by **simes** » Tue May 24, 2005 11:43 am

Doh!

I was approaching from the other side. I stand corrected!

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