In general, no. A simple deadly pattern should have each base candidate in the concerned cells show up twice in every group that they are a part of. In your pattern, the 7 and 9 only show up once in columns 2 and 3, therefore, what you have shown is not a deadly pattern where uniqueness would apply. Now if you had...
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+----------+-----------+-----------+
| . . . | . . . | . . . |
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+----------+-----------+-----------+
| . 79 . | . . . | 79 . . |
| . . 79 | . . . | 279 . . |
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+----------+-----------+-----------+
| . 79 79 | . . . | . . . |
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+----------+-----------+-----------+
or
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+----------+-----------+-----------+
| . . . | . . . | . . . |
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| . 57 57 | . . . | . . . |
+----------+-----------+-----------+
| . 79 . | . . . | 79 . . |
| . . 79 | . . . | 279 . . |
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+----------+-----------+-----------+
| . 59 59 | . . . | . . . |
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+----------+-----------+-----------+
...then you do have a deadly pattern where each base candidate shows up twice in their groups, and you can assert that r5c7 = 2.
[edit: fixed goof in second grid caught by Vidar
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