- Code: Select all
+-------------------+-------------------+-------------------+
| 1 4 3 | 5 9 67 | 2 68 678 |
| 7 2 6 | 4 8 1 | 9 3 5 |
| 8 5 9 | 2 67 3 | 1467 146 167 |
+-------------------+-------------------+-------------------+
| 5 8 4 | 69 1 679 | 67 2 3 |
| 6 9 17 | 3 57 2 | 1578 18 4 |
| 3 17 2 | 8 4 567 | 1567 9 167 |
+-------------------+-------------------+-------------------+
| 49 137 178 | 169 56 4569 | 13468 1468 2 |
| 2 6 18 | 7 3 49 | 148 5 189 |
| 49 13 5 | 169 2 8 | 1346 7 169 |
+-------------------+-------------------+-------------------+
We often find that there are multiple techniques which will get the same result to help solve or advance a puzzle, but here we have two separate XYZ Wings waiting to take off in the same Box. I found it interesting (but perhaps not surprising) that whichever one you choose to work through, it destroys the other but still gives the same eliminations.
1) r4c46 forms an XYZ Wing with r1c6, so -6r6c6 => -7r4c6 => 7r4c7 or
2) r5c5 & r6c6 form an XYZ Wing with r1c6, so -7r4c6 => -6r6c6 and 7r4c7
Both routes solve r4c7 for 7 and leave Box 5 with two bi-value pairs.
But where do we go from here?