The New Sudoku Players' Forum

[gklittle]

Hi, I'm still fairly new to the puzzles and trying to learn all the techniques. I've worked this puzzle 4 times and end up in the same place. Please tell me what I am not seeing here in order to continue. Thanks.




1(56)(47)9(24)(356)(237)(2378)(78)
9 3 2 1 8 7 4 6 5
(56)8(47)(356)(24)(356)(237)19
(57)(21)3(47)6(59)8(2579)(147)
4(56)82(59)1(567)(579)3
(567)(21)9(47)38(12567)(257)(1467)
27(156)(3568)(159)(3569)(1356)4(168)
34(156)(568)729(58)(168)
89(156)(356)(15)4(13567)(357)2

[bennys]

in row 5 the 7 must be in the third box so you can eliminate the other 7's from that box and you get that r1c9 is 7

[gklittle]

Thank you so much, Bennys. I can't believe I missed that each time. Puzzle solved!!

[Cec]

in row 5 the 7 must be in the third box so you can eliminate the other 7's from that box and you get that r1c9 is 7

Hi bennys

I can see how candidate 7's are locked in row 5 (Box 6) -you refer to this as Box 3 and which enables the remaining 7's in this box to be eliminated.

There are some naked pairs (59) in box 5 which gives another naked pair (47) in this same box (c4) and another naked pair (56) in c2 (boxes 1 and 4) but interested to know how you determine that a 7 goes in cell r1c9. (box3).

Bonsai Cec

[bennys]

After you eliminate the 7's from the other cells in boxs 3 the only 7 candidat in c9 is in r1

[stuartn]

The only 7's in R5 are in Box 6. This removes the candidate 7's from R4 and R6 in Box 6. This makes the 7 in Box 3 unique in C9.

stuartn

[Cec]

Thanks to all above. Still kicking myself for omitting to include clue 2 in cell r9c9 which gave me another candidate 7 in this cell and hence not seeing what is now obvious. Lesson for Cec? Measure twice - cut once.

Bonsai Cec