Bigtone53 wrote:"...Look at box 1. r3c3 has to be a 4. Consider boxes 1,4,7, adding up to 135. r9c3 has to be a 2, so r9c4 has to be a 7. Consider rows 6,7,8.9. These 4 rows add up to 180 so r5c9 is a 4
and so on...."
I'm sure I am missing something - yes, I know what you're thinking when I say that
- but I still don't get this.
I can see why r9c3 has to be a
2 but I don't understand why r3c3 has to be a
4. As the numbers to be placed in each of the three cells in column 3 (r345c3) must total
17 then why is cell r3c3 restricted to
4? With a
2 later placed in r9c3 following
Bigtone's above comments then there are alternative choices for different numbers between 1 to 9 (excluding
2 of course) which could be placed in r345c3 and still give a total of
17.
On the matter of posting this puzzle in the wrong forum, I too agree with
Ronk's above post that the puzzle should belong in the Sudoku Variants Forum. That said,
Bigtone's comments are also relevant as to how this "problem" can be avoided.
Cec