Yes, that's it, you can start with the UR like this:
- Code: Select all
+-------------------------+-------------------------+-------------------------+
| 179 3 #127 |#1249 49 6 | 5 479 8 |
| 189 4 #12 |#12359 3589 7 | 19 6 139 |
| 5 1689 167 | 1349 3489 148 | 149 3479 2 |
+-------------------------+-------------------------+-------------------------+
| 6 1259 12345 | 7 3458 1458 | 2489 24589 459 |
| 349 7 345 | 3456 2 458 | 4689 1 4569 |
| 14 125 8 | 1456 456 9 | 3 2457 4567 |
+-------------------------+-------------------------+-------------------------+
| 148 1568 9 | 2456 456 3 | 7 2458 1456 |
| 3478 568 34567 | 24569 1 245 | 24689 234589 34569 |
| 2 156 134567 | 8 45679 45 | 1469 3459 134569 |
+-------------------------+-------------------------+-------------------------+
There has to be a solution without 2r2c3, but every such solution (NS r2c3, HSs 1r1, 2b12) contains the UR, meaning there is a solution with the UR.
The two solutions of the UR are equivalent, so there is a solution with the UR and 2r2c3, which obviously is a solution to the original puzzle.
So setting 12r12c34, you are still guaranteed a solution. stte
Marek