by **Karyobin** » Mon Sep 19, 2005 10:33 am

Right, the order I did it is as follows:

1. There are 8's locked in a row in block 4. This means you can remove 8's as candidates from block 6 row 5.

2. There are 3's locked in a column in block 1, which means you can remove 3's as candidates in block 4.

3. Use the x-wing in cells r2c6, r2c7, r8c6 and r8c7 to remove some candidate 8's in columns 6 and 7.

4. There is now only one place for an 8 in block 6, which removes the 8 as a candidate from r1c9. The hidden triple in 4's, 8's and 9's is now more obvious in block 3. At this point you can also place a '5' in block 6, as there's only one place it can go.

5. There are 3's locked in a row in block 3, so you can remove candidate 3's from row 3, blocks 1 and 2.

6. Now, you have the naked pair {1,6} in column 5, exposing a '4' in r5c5 and subsequently a '5' in r4c5.

The rest is easy, complete row 4, complete block 4, continue ad nauseam.

Sorry silvercar, you must have a very masculine writing style. ;-)