Am I correct in finding that this puzzle does not have a unique solution? Solving logically, I am down to 6 squares - three pairs, in boxes 2, 5, and 8. In box 2, the missing numbers are 5 and 8; in box 5, numbers 1 and 8 are missing; and in box 8, numbers 1 and 2. There seem to be two distinct ways of completing the puzzle, but no single unique solution. Or have I gone wrong somewhere??
John, Sevenoaks