by CathyW » Thu Sep 29, 2005 1:27 pm
Before I put pen to paper (should probably use pencil so I can rub it out!) - am I right in thinking I can eliminate 4 and 5 as candidates from the 9 cage (r8c7 and r9c7) because the 7 cage has to be 2+5 or 3+4 - either option would rule out 4 and 5 in the 9 cage. Seems logical but just checking as brain seems to be on a go slow today. Still left with 6 or 8 in r8c7 though (with corresponding 3 or 1 in r9c7).