Thunderstorm

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Thunderstorm

Code: Select all
`+-------+-------+-------+| 9 . 8 | 7 . . | . . . || 6 . . | . . 5 | . . . || . . 4 | 8 . 3 | . . . |+-------+-------+-------+| . . . | . 2 . | 1 9 . || . . . | 1 . . | . 5 7 || . . 9 | . . . | . . 4 |+-------+-------+-------+| . . . | 3 . . | 7 . . || . . 2 | . . . | 4 6 . || . 1 . | . . . | . 3 2 |+-------+-------+-------+9.87.....6....5.....48.3.......2.19....1...57..9.....4...3..7....2...46..1.....32`
mith

Posts: 301
Joined: 14 July 2020

Re: Thunderstorm

My most reasonable solution, two steps (Almost ALS XZ rule and almost ALS Y-Wing) :
Code: Select all
` +------------------------+------------------------+----------------------+ |  9      235     8      |  7      146     146    |  256-3  124   1356   |  |  6      37      1      |  2      49      5      |  89-3   478   389    |  |  257    257     4      |  8      169     3      |  2569   127   1569   |  +------------------------+------------------------+----------------------+ |  4578   45678   3567   |  456    2       4678   |  1      9     368    |  |  248    2468    36     |  1      3468    9      |  2368   5     7      |  |  1      25678   9      |  56     35678   678    |  2368   28    4      |  +------------------------+------------------------+----------------------+ |  458    45689   56     |  3      14568   2      |  7      18    1589   |  |  3      5789    2      |  59     1578    178    |  4      6     1589   |  |  4578   1       567    |  4569   45678   4678   |  589    3     2      |  +------------------------+------------------------+----------------------+`

1. [(3=164)r1c569 - (4=893)r2c589] = (5)r1c9 - r13c7 = (5-9)r9c7 = r9c4 - (9=5)r8c4 - r46c4 = (5-3)r6c5 = (3)r6c7 => -3 r1c7
2. [(3=7)r2c2 - (725=6)r3c127 - (6=283)b6p478] = (9)r3c7 - r9c7 = r9c4 - (9=5)r8c4 - r46c4 = (5-3)r6c5 = (3)r6c7 => -3 r2c7; lclste

Presented as kraken AALS's:
Hidden Text: Show
1. Almost-almost NT(164)r1c569
(164)r1c569 - (4=893)r2c579
(3)r1c9
(5)r1c9 - r13c7 = (5-9)r9c7 = r9c4 - (9=5)r8c4 - r46c4 = (5-3)r6c5 = (3)r6c7
------------------
=> -3 r1c7

2. Almost-almost NT(257)r3c7
(257)r3c127 - (7=3)r2c2
(6)r3c7 - (6=283)b6p478
(9)r3c7 - r9c7 = r9c4 - (9=5)r8c4 - r46c4 = (5-3)r6c5 = (3)r6c7
-------------------
=> -3 r2c7; lclste
Cenoman
Cenoman

Posts: 1517
Joined: 21 November 2016
Location: Paris, France

Re: Thunderstorm

Cenoman wrote:My most reasonable solution, two steps (Almost ALS XZ rule and almost ALS Y-Wing) :

Very nice!

SpAce

Posts: 2568
Joined: 22 May 2017

Re: Thunderstorm

Agreed!

(There is a one step solution though. )
mith

Posts: 301
Joined: 14 July 2020

Re: Thunderstorm

Hint: This puzzle is a bit of a troll. It does not require any chains.
mith

Posts: 301
Joined: 14 July 2020

Re: Thunderstorm

Ah, how could i miss that ?
So lets swap bands 1,2 and stacks 2,3 to get a 180° rotational symmetric puzzle in normal form,
with digit pairs 12,39,47,56 and 88 (you can always find the other digit in the cell "mirrored" by the center)
Code: Select all
`+-------+-------+-------+| . . . | 1 9 . | . 2 . || . . . | . 5 7 | 1 . . || . . 9 | . . 4 | . . . |+-------+-------+-------+| 9 . 8 | . . . | 7 . . || 6 . . | . . . | . . 5 || . . 4 | . . . | 8 . 3 |+-------+-------+-------+| . . . | 7 . . | 3 . . || . . 2 | 4 6 . | . . . || . 1 . | . 3 2 | . . . |+-------+-------+-------+`

We can immediately put an 8 into the center (the only digit symmetric to itself) -> stte
(in the original puzzle the 8 goes to r2c8)
eleven

Posts: 2461
Joined: 10 February 2008

Re: Thunderstorm

Yep, that's it.

It occurred to me that when Gurth's applies, it also applies to any morphs... it's just some are obviously easier to spot than others. For the particular case of being able to divide the grid into a 3x6, 3x3, 6x6, and 6x3 that are all rotational symmetric and all share the same digit pairings, it's not too hard to see that the symmetry applies. (And I happened to have a 9.0 which reduces to singles with Gurth's, so...)

I'm wondering if there is some simple generic process for determining whether a puzzle is a potential candidate for morphing in this way. In such a puzzle, there must necessarily be a pairing between rows, columns, and boxes, but maybe that's not a sufficient condition.
mith

Posts: 301
Joined: 14 July 2020

Re: Thunderstorm

If i had studied it better, i should have had the idea, that it is symmetric, because the same move can always be done for 2 digits, starting with the singles for 1/2 and 3/9.
(Also in Cenoman's solution you can have the same, if you replace the digits/cells by their symmetric counterparts.)

My method to find the symmetry is basically, to look at the boxes. Only boxes with the same number of candidates can be symmetric to each other, and they must have patterns, which can be mapped to each other with row/column swaps.
eleven

Posts: 2461
Joined: 10 February 2008

Re: Thunderstorm

Great example. It's the first time I see symmetry being applied to find a solution.
denis_berthier
2010 Supporter

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Joined: 19 June 2007
Location: Paris