The New Sudoku Players' Forum

[5krunner]

I'm an intermediate a Sudoku but his is supposedly an easy puzzle ... however, I'm stumped. Any one have a suggestion on the nexts step? Thank you!!

x 4 x ! 7 x 6 ! 3 x x
3 x x ! x 1 x ! 8 x x
5 x 1 ! 4 3 x ! 8 x x
------+-------+------
4 x x ! x 7 x ! x 8 9
7 2 9 ! 8 4 1 ! x 3 x
8 x x ! x 5 x ! x x 7
------+------+-------
x x 4 ! 1 x x ! 9 x 3
1 x x ! x 2 x ! x x x
x x 7 ! 3 x 4 ! x 5 x

[Carcul]

Hi 5krunner.

In your puzzle there are two "8" in column seven. You have to correct the grid.

Regards, Carcul

[Pat]

this is supposedly an easy puzzle

however, I'm stumped

Code: Select all

 . 4 . | 7 . 6 | 3 . .
 3 . . | . 1 . | . . .
 5 . 1 | 4 3 . | 8 . .
-------+-------+------
 4 . . | . 7 . | . 8 9
 7 2 9 | 8 4 1 | . 3 .
 8 . . | . 5 . | . . 7
-------+-------+------
 . . 4 | 1 . . | 9 . 3
 1 . . | . 2 . | . . .
 . . 7 | 3 . 4 | . 5 .

the 2 for box 7 must be in c1

this settles r1c1

- Pat

[5krunner]

Sorry ... here's the corrected puzzle:

x 4 x ! 7 x 6 ! 3 x x
3 x x ! x 1 x ! x x 4
5 x 1 ! 4 3 x ! 8 x x
------+-------+------
4 x x ! x 7 x ! x 8 9
7 2 9 ! 8 4 1 ! x 3 x
8 x x ! x 5 x ! x x 7
------+------+-------
x x 4 ! 1 x x ! 9 x 3
1 x x ! x 2 x ! x x x
x x 7 ! 3 x 4 ! x 5 x

[ihope127]

After a pinned square, the rest is forced moves. Here's the pin:

The pin is R1C9, which has to be 5.

[tso]

Only one cell in row one can still take a 5.

[MCC]

5krunner

It would help us to help you if in future you would post your candidate list at the same time you post the puzzle you're stuck on.

This is the candidate list for your puzzle, I'll assume this is where you're at.

Code: Select all

29    4     28  |7    89   6    |3     129   125
3     6789  268 |259  1    2589 |2567  2679  4 
5     679   1   |4    3    29   |8     2679  26 
------------------------------------------------
4     1356  356 |26   7    23   |126   8     9 
7     2     9   |8    4    1    |56    3     56 
8     136   36  |269  5    239  |1246  1246  7   
------------------------------------------------
26    568   4   |1    68   578  |9     267   3   
1     35689 3568|59   2    5789 |467   467   68 
269   689   7   |3    689  4    |126   5     128

Naked triplet in r1 enables you to place two numbers in box 3
The 2's are locked in c1 box7. So r1c1 can be placed.

That should see you on your way.

MCC

[tso]

This is an easy puzzle that does not require candidates -- it is solved completely using nothing but singles.

[ihope127]

This is an easy puzzle that does not require candidates -- it is solved completely using nothing but singles.

One single.

[QBasicMac]

29 4 28 7 89 6 3 129 125
Naked triplet in r1 enables you to place two numbers in box 3

Please help old bad-eye's here. Which three cells above constitute the naked triplet?

Thanks

Mac

[tso]

This is an easy puzzle that does not require candidates -- it is solved completely using nothing but singles.

One single.

One hidden, many naked.

What you're calling a pin, I'm calling a hidden single.
What you're calling a forced move, I'm calling a naked single.

29 4 28 7 89 6 3 129 125
Naked triplet in r1 enables you to place two numbers in box 3

Please help old bad-eye's here. Which three cells above constitute the naked triplet?

Thanks

Mac

[29][28][89] is a naked triple. This is a perfectly valid triple making perfectly valid eliminations -- though again, the pin or hidden single followed by forced moves/naked singles is the simpler way to go and does not require candidates to be filled in. But if your goal is NOT to do things the simple way, this is actually a way to make easy puzzles like this more interesting, there are *lots* of more complex tactics available. There is another triple available -- row346c6 is a triple in [239]. Better (or worse), there is a 4 cell nice loop in r17c15...

Code: Select all

 *--------------------------------------------------------------------*
 |29------------(9)-------------89      .      | .      .      .      |
 | |      .      .      | .      |      .      | .      .      .      |
 | |      .      .      | .      |      .      | .      .      .      |
 |-|--------------------+--------|-------------+----------------------|
 |(2)     .      .      | .     (8)     .      | .      .      .      |
 | |      .      .      | .      |      .      | .      .      .      |
 | |      .      .      | .      |      .      | .      .      .      |
 |-|--------------------+--------|-------------+----------------------|
 |26------------(6)-------------68      .      | .      .      .      |
 | .      .   .  .      | .      .      .      | .      .      .      |
 | .      .      .      | .      .      .      | .      .      .      |
 *--------------------------------------------------------------------*

... eliminating 9s from the rest of the top row, 6s from the rest of row 7, 2s from the rest of column 1 and 8s from the rest of column 5.

Again, a perfectly valid deduction, very possibly more fun than simply filling in all the singles.

[ihope127]

One hidden, many naked.

What you're calling a pin, I'm calling a hidden single.
What you're calling a forced move, I'm calling a naked single.

Aha. Hadn't really thought of them as naked singles.

[5krunner]

Thank you everyone for the excellent advise. I'm slowly learning.

[QBasicMac]

[29][28][89] is a naked triple

Thanks!! I don't know how long I could stare at that line and not see it.

Mac

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