Here is a puzzle that may take a swordfish and a UR1 to get to a BUG+2 that, like a quantum BUG, solves the puzzle without using the BUG, seeing it is enough.
This is a puzzle that Cluadiarabia almost published at Havard's fine site.
http//www.sudoku.frihost.net/sudokus/03Oct2006_174633_fast_dopel_randl10.sud
There she suggested a variant, which has BUGs, listed below.
- Code: Select all
8 . . | . . . | . . 2
. . . | . . . | . . .
. . 4 | 3 . 6 | 5 . .
---------------------
. . 3 | . 1 . | 4 . .
. . . | 9 . 7 | . . .
. . 5 | . 8 . | 3 . .
---------------------
. . 6 | 5 . 4 | 1 . .
. . . | . . . | . . .
2 . . | . . . | . . 7
Various methods and a UR1 get us to this position.
- Code: Select all
*--------------------------------------------------*
| 8 5 79 | 17 4 19 | 6 3 2 |
| 3 6 29 | 28 5 89 | 7 1 4 |
| 1 27 4 | 3 27 6 | 5 89 89 |
|----------------+----------------+----------------|
| 79 #28 3 | 6 1 5 | 4 27 89 |
| 4 1 28 | 9 3 7 | 28 6 5 |
| 6 79 5 | 4 8 2 | 3 79 1 |
|----------------+----------------+----------------|
| 79 *789 6 | 5 27 4 | 1 28 3 |
| 5 3 *178 | 27 9 18 | 28 4 6 |
| 2 4 18 | 18 6 3 | 9 5 7 |
*--------------------------------------------------*
BUG+2 suggests that R7C2 is 7 or R8C3 is 8. In either case R7C2 is not 8 which forces R4C2 = 8. Simple puzzle, now!