Mauricio wrote:Some kind of heart
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. . . . . . . . .
. . . 1 . 2 . . .
. . 1 . 3 . 4 . .
. . 4 . . . 1 . .
. . 5 . . . 3 . .
. 2 . 6 . 7 . 8 .
. . . . 5 . . . .
. 7 . . . . . 6 .
. 8 . . . . . 2 .
Couldn't resist in solving this beautiful heart:
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*-----------*
|6..|...|2..|
|...|1.2|6..|
|2.1|836|4.7|
|---+---+---|
|..4|...|1..|
|..5|...|3..|
|.2.|6.7|.8.|
|---+---+---|
|..6|258|7..|
|.72|...|86.|
|.8.|76.|.2.|
*-----------*
*--------------------------------------------------------------------*
| 6 349 78 | 459 479 459 | 2 139 1389 |
| 349 3459 78 | 1 479 2 | 6 359 389 |
| 2 59 1 | 8 3 6 | 4 59 7 |
|----------------------+----------------------+----------------------|
| 78 69 4 | 35 28 35 | 1 79 26 |
| 78 169 5 | 49 28 149 | 3 479 26 |
| 139 2 39 | 6 149 7 | 59 8 459 |
|----------------------+----------------------+----------------------|
| 1349 1349 6 | 2 5 8 | 7 1349 1349 |
| 13459 7 2 | 349 149 1349 | 8 6 13459 |
| 13459 8 39 | 7 6 1349 | 59 2 13459 |
*--------------------------------------------------------------------*
From this early point I laid a forcing chain eliminating the 4 in r6c9 -> r45c8=79 -> r3c8=5 -> r2c8=3 -> r1c2=3 and r3c2=9 -> r4c2=6 -> r5c2=1 -> r7c2=4 -> r7c98 = -4 -> r89c9=4 <> r6c9=4
With finding this contradiction in column 9, the puzzle can be solved easily by singles and one pair.
Claudia