i need help with this one. i know it isn't too hard, but, yeah. just need pointers.

7 posts
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i need help with this one. i know it isn't too hard, but, yeah. just need pointers.

- sudoku_n00b
**Posts:**1**Joined:**01 March 2006

This puzzle solves with nothing but singles. In box 3 (top right 3X3 box), look to see where a 2 can be placed, as only one cell in that box has that for a candidate. Then do the same for row 7, 8 and 9 (1 is the top row). Now do that for each number and you'll solve the puzzle.

On left-hand side of the homepage of this website there is a menu of links. Click on the one called 'how to solve'. It explains some basic techniques, which should enable you to solve this puzzle.

Tracy

On left-hand side of the homepage of this website there is a menu of links. Click on the one called 'how to solve'. It explains some basic techniques, which should enable you to solve this puzzle.

Tracy

Last edited by TKiel on Thu Mar 02, 2006 12:16 am, edited 1 time in total.

- TKiel
**Posts:**209**Joined:**05 January 2006

MCC wrote:Looking at the symmetry it looks like nothing has been added to the original puzzle at all.

MCC

MCC, unless I'm missing something has this post gone to the right thread?

Cec

- Cec
**Posts:**1039**Joined:**16 June 2005

sudoku_n00b,

Here rows are number 1-9 starting at the top and going down.

Columns are numbered 1-9 starting at the left and going right.

Boxes are numbered 1-3 at the top 4-6 in the middle and 7-9 at the bottom.

OK, look at Box 7, see row 7, column 3. (r7c3)? It is a 4.

It is a 4, thus there can be no more 4's on row 7 or in Box 7, right?

Now r8c4=4 also. So no more 4's on row 8 or in box 8.

Well, Box 9 needs a 4 somewhere. Where can it go?

Right: Either r9c7 or r9c8.

But look up. Above r9c8 is already a 4! So it can't go here.

That leaves only one place: r9c8. You can write a 4 there now.

Keep looking for patterns like that. When there are no more, try this:

Take a row that has som numbers already placed. The more, the better. Then figure out what digits are missing. These have to go into the remaining cells. So one-at-a-time, look at the cells and see if you can eliminate all but one candidate.

For example if you had a row like this:

425 8-1 --3

Then you see that 679 are missing.

Look at the - in 8-1 and see if 6, 7, or 9 are impossible. IF TWO OF THEM are impossible, then it HAS to be the other one. Stick it there.

Well, give it a try and work hard. If you get stuck, post where you got to so we can help.

Mac

Here rows are number 1-9 starting at the top and going down.

Columns are numbered 1-9 starting at the left and going right.

Boxes are numbered 1-3 at the top 4-6 in the middle and 7-9 at the bottom.

OK, look at Box 7, see row 7, column 3. (r7c3)? It is a 4.

It is a 4, thus there can be no more 4's on row 7 or in Box 7, right?

Now r8c4=4 also. So no more 4's on row 8 or in box 8.

Well, Box 9 needs a 4 somewhere. Where can it go?

Right: Either r9c7 or r9c8.

But look up. Above r9c8 is already a 4! So it can't go here.

That leaves only one place: r9c8. You can write a 4 there now.

Keep looking for patterns like that. When there are no more, try this:

Take a row that has som numbers already placed. The more, the better. Then figure out what digits are missing. These have to go into the remaining cells. So one-at-a-time, look at the cells and see if you can eliminate all but one candidate.

For example if you had a row like this:

425 8-1 --3

Then you see that 679 are missing.

Look at the - in 8-1 and see if 6, 7, or 9 are impossible. IF TWO OF THEM are impossible, then it HAS to be the other one. Stick it there.

Well, give it a try and work hard. If you get stuck, post where you got to so we can help.

Mac

- QBasicMac
**Posts:**441**Joined:**13 July 2005

7 posts
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