Leren wrote:Well, as long as we allow moves that read like the flow chart of the autopilot of a Boeing 787, here goes. One move :
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*--------------------------------------------------------------------------------*
| 8 9 35 | 56 256 1 | 3467 357-4 2567 |
| 17 167 35 | 4 2569 KC:5679 | 8 359 2569 |
| 4 67 2 | 5689 3 56789 | 69 59 1 |
|--------------------------+--------------------------+--------------------------|
| 6 45 1 | 7 4589 34589 | 2 3589 589 |
| 2 45 7 | 5689 45689 345689 | 369 1 5689 |
| 9 3 8 | 2 1 56 | 67 57 4 |
|--------------------------+--------------------------+--------------------------|
| 15 8 6 | 59 7 459 | 149 2 3 |
| 3 2 9 | 1 468 468 | 5 478 78 |
| 157 17 4 | 3 589 2 | 19 6 89 |
*--------------------------------------------------------------------------------*
Kraken Cell r2c6 :
4r1c8 - 4r8c8 = (4-1) r7c7 = 1r9c7 - 1r9c2 = (1-6) r2c2 = 6r3c2 - (6=9) r3c7 - (9=5) r3c8 - 5r6c8 = 5r6c6 - 5 r2c6
4r1c8 - 4r8c8 = (4-1) r7c7 = (1-5) r7c1
4r1c8 - 4r8c8 = (4-1) r7c7 = 1r9c7 - 1r9c2 = (1-6) r2c2 = 6r3c2 - (6=9) r3c7 - (9=5) r3c8 - 5r6c8 = 5r6c6 - 5r7c6 *= 5r7c4 - (5=6) r1c4 - 6 r2c6
4r1c8 - 4r8c8 = (4-1) r7c7 = 1r7c1 - (1=7) r2c1 - 7 r2c6
4r1c8 - 4r8c8 = (4-1) r7c7 = (1-5) r7c1
4r1c8 - 4r8c8 = (4-9) r7c7
4r1c8 - 4r8c8 = (4-1) r7c7 = 1r9c7 - 1r9c2 = (1-6) r2c2 = 6r3c2 - (6=9) r3c7 - (9=5) r3c8 - 5r6c8 = 5r6c6 - 5r7c6 *= 5r7c4 - 9r7c4 *= 9r7c6 - 9 r2c6
=> - 4 r1c8; stte
Leren
With a lighter airplane than the Boeing 787, reach destination in a shorter route:
(keeping Leren's solution layout, in order to compare line per line, with 9r3c7 as a target)
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Kraken Cell r2c6 :
9r3c7 - (9=5) r3c8 - 5r6c8 = 5r6c6 - 5 r2c6
9r3c7 - (9=1)r9c7 - (17=5)r9c12 - 5r7c1
9r3c7 - (9=5) r3c8 - 5r6c8 = 5r6c6 - 5r7c6 *= 5r7c4 - (5=6) r1c4 - 6 r2c6
9r3c7 - (9=1)r9c7 - (1=7)r9c2 - 7r9c1 = 7r2c1 - 7 r2c6
9r3c7 - (9=1)r9c7 - (17=5)r9c12 - 5r7c1
9r3c7 - 9r7c7
9r3c7 - (9=5) r3c8 - 5r6c8 = 5r6c6 - 5r7c6 *= 5r7c4 - 9r7c4 *= 9r7c6 - 9 r2c6
=> -9 r3c7; ste
Or presented as a net, avoiding duplicata as much as possible:
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(5)r2c6 - r6c6 = r6c8 - (5=9)r3c8 -9 r3c7
||
(7)r2c6 - r2c1 = r9c1 - (7=1)r9c2 - (1=9)r9c7 -9 r3c7
||
(6)r2c6 - (6=5)r1c4 - (5)r7c4
|| \\
|| (5)r7c6 - r6c6 = r6c8 - (5=9)r3c8 -9 r3c7
|| ||
|| (5)r7c1 - (5=71)r9c12 - (1=9)r9c7 -9 r3c7
|| //
(9)r2c6 - (9)r7c6 = (9-5)r7c4
||
(9)r7c7 -9 r3c7
=> -9 r3c7; ste
Any taker to write it as an AIC ?
EDIT: nothing new in the logic, compared to Leren's solution. Work on presentation only.