Hello. First, you haven't actually exhausted all basics. There's a naked pair (48) / hidden pair (69) on row 2, as well as a hidden pair (69) / naked quad (2458) on column 4. They don't really make a difference, though.
This puzzle requires at least one relatively advanced technique (AIC or Sue de Coq, for example) to solve. There are a couple of simpler Unique Rectangles and a W-Wing available, but they're not enough to solve the puzzle. The simplest single move that leaves just singles is probably this short AIC (or one of its variants):
- Code: Select all
.-----------------.------------------.--------------.
| 6 3 9 | 458 2 458 | 7 1 48 |
| 5 7 1 | 4689 4689 48 | 3 2 48 |
| 8 2 4 | 7 3 1 | 9 6 5 |
:-----------------+------------------+--------------:
| 1 d(8)-4 6 | 2458 4578 9 |a2(4) 57 3 |
| 47 9 c278 | 3 4578 6 |b24 57 1 |
| 347 5 237 | 24 1 247 | 6 8 9 |
:-----------------+------------------+--------------:
| 347 468 378 | 1 678 378 | 5 9 2 |
| 2 68 358 | 5689 5689 358 | 1 4 7 |
| 9 1 57 | 245 457 2457 | 8 3 6 |
'-----------------'------------------'--------------'
(4=2)r4c7 - r5c7 = (2-8)r5c3 = (8)r4c2 => -4 r4c2; stte
The chain proves that either r4c7=4 or r4c2=8; in both cases r4c2<>4. Once you eliminate that, the rest is easy.
PS. If I'm not wrong, some people call that chain pattern an H2-Wing. But I may very well be wrong, so I'd appreciate if someone either confirmed or corrected that. (Not that it really matters what it's called as long as it works.)